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Taya2010 [7]
3 years ago
13

Rutherford's research was primarily involved with: electron distribution defining the components of nuclei using electromagnetic

energy
Chemistry
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer is: defining the components of nuclei.

Rutherford theorized that atoms have their charge concentrated in a very small nucleus.

This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).  

Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.

That is different from Plum Pudding model, because it shows that most of the atom is empty space.

Rutherford conducted research that led to the first splitting of the atom in a nuclear reaction.

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You are given the reaction Cu + HNO3 Cu(NO3)2 + NO + H2O complete the final balanced equation based on half-reactions
Evgen [1.6K]

Answer:

3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

Explanation:

Cu + HNO3 → Cu(NO3)2 + NO + H2O

The first step is to write the oxidation numbers for each atoms in the given equation  

Cu0 + H+1N+5O-23 → Cu+2(N+5O-23)2 + N+2O-2 + H+12O

Identify the oxidizing and reducing agent  

OXIDATION --- Cu0 → Cu+2(N+5O-23)2 + 2e-    

REDUCTION---H+1N+5O-23 + 3e- → N+2O

Balance equation in half reaction  

Cu0 + 2HNO3 → Cu+2(N+5O-23)2 + 2e-

H+1N+5O-23 + 3e- → N+2O

Now balance the charge

Cu0 + 2HNO3 → Cu+2(N+5O-23)2 + 2e- + 2H+

H+1N+5O-23 + 3e- + 3H+ → N+2O

Balance the oxygen atom  

Cu0 + 2HNO3 → Cu+2(N+5O-23)2 + 2e- + 2H+

H+1N+5O-23 + 3e- + 3H+ → N+2O-2 + 2H2O

Make electron gain equivalent to electron lost.

3Cu0 + 6HNO3 → 3Cu+2(N+5O-23)2 + 6e- + 6H+

2H+1N+5O-23 + 6e- + 6H+ → 2N+2O-2 + 4H2O

Complete reaction  

3Cu0 + 8H+1N+5O-23 + 6e- + 6H+ → 3Cu+2(N+5O-23)2 + 2N+2O-2 + 6e- + 4H2O + 6H+

Simplify the equation

3Cu0 + 8H+1N+5O-23 → 3Cu+2(N+5O-23)2 + 2N+2O-2 + 4H2O

Final equation  

3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

5 0
3 years ago
How many atoms of oxygen are represented in 2Fe(NO3)2? ( My answer: C) Correct?
astra-53 [7]

How many atoms of oxygen are represented in 2Fe(NO3)2?

Answer: 12

3 0
3 years ago
How many moles are there in 6.33x10^23 molecules of NH3?
nadezda [96]
About 1.051 moles (depends on how u round it)
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What gas is used in freezers and fridges? ​
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Answer:

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Explanation:

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