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Air-bags can be inflated by the decomposition of sodium azide, NaN3. At 25.0◦C and 1.10 atm, what volume of N2(g) is produced by

Mashcka [7]

Answer:

V = 36.7L of $N_{2}$

Explanation:

1. Write the chemical reaction for the decomposition of sodium azide:

$_{2}NaN_{3}(l)=_{2}Na(s)+_{3}N_{2}(g)$

2. Find the number of moles of $N_{2}$ produced by the decomposition of 71.4g of $NaN_{3}$ :

$71.4gNaN_{3}*\frac{1molNaN_{3}}{65gNaN_{3}}*\frac{3molesN_{2}}{2molesNaN_{3}}=1.65molesN_{2}$

3. Use the ideal gas equation to find the Volume of $N_{2}$ occupied by 1.65 moles of $N_{2}$ , at the temperature and pressure given by the problem:

$PV=nRT$

Solving for V:

$V=\frac{nRT}{P}$

Converting the temperature from ◦C to K:

25◦C+273.15=298.15K

Replacing values:

$V=\frac{1.65mol*(0.082\frac{atm.L}{mol.K})*298.15K}{1.10atm}$

V=36.7L of $N_{2}$

4 0

3 years ago

A 800g/cm³ boulder has a density of 8g/cm³ what is the volume

PilotLPTM [1.2K]

6400 cubic centimeters

3 0

4 years ago

What is the difference between docosahexaenoate (DHA) and 19,20-dihydroxydocosapentaenoate (19,20-DHDP)? Only DHA is a polyunsat

andrew11 [14]

Answer:

Explanation:

The correct answer is 19, 20 DHDP is more polar than DHA. This is as a result of the presence of two hydroxyl groups.

4 0

4 years ago

Cobalt-60 and iodine-131 are radioactive isotopes that are used in

svlad2 [7]

Cobalt 60-Used to treat certain types of cancer.
Iodine-131-Used to monitor and treat goiter and other thyroid problems.It is also used to treat liver and brain tumor
Mark me as the Brainliest❤️❤️✌✌

8 0

3 years ago

A 500.0 g block of dry ice (solid CO2, molar mass = 44.0 g) vaporizes at room temperature. Calculate the volume of gas produced

Damm [24]

Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

<h3>Definition of ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

<h3>Ideal gas law</h3>

An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

<h3>Volume of gas</h3>

In this case, you know:

P= 1.50 atm
V= ?
n= 500 g× $\frac{1 mole}{44 g}$ = 11.36 moles, being 44 $\frac{g}{mole}$ the molar mass of CO₂
R= 0.082 $\frac{atmL}{molK}$
T= 25 C= 298 K (being 0 C=273 K)

Replacing in the ideal gas law:

1.50 atm×V = 11.36 moles×0.082 $\frac{atmL}{molK}$ × 298 K

Solving:

V= (11.36 moles×0.082 $\frac{atmL}{molK}$ × 298 K) ÷ 1.50 atm

Finally, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

Learn more about the ideal gas law:

<u>brainly.com/question/4147359?referrer=searchResults</u>

4 0

2 years ago