Need help please!!!!!!!!

Explain whether areas B and D show the same season.

torisob [31]

They do not show the same season. one is faced a different part of the sun

4 0

2 years ago

Electrochemistry - Equilibrium

Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K

E⁰cell = 1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298 lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298 lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

8 0

2 years ago

2 NO + O22 NO2 is second order in NO and first order in O2. Complete the rate law for this reaction in the box below. Use the fo

riadik2000 [5.3K]

Answer : The value of rate of reaction is $1.35\times 10^{-8}Ms^{-1}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical equation is:

$2NO+O_2\rightarrow 2NO_2$

Rate law expression for the reaction is:

$\text{Rate}=k[NO]^a[O_2]^b$

As per question,

a = order with respect to $NO$ = 2

b = order with respect to $O_2$ = 1

Thus, the rate law becomes:

$\text{Rate}=k[NO]^2[O_2]^1$

Now, calculating the value of rate of reaction by using the rate law expression.

Given :

k = rate constant = $9.87\times 10^3M^{-2}s^{-1}$

[NO] = concentration of NO = $7.86\times 10^{-3}M$

$[O_2]$ = concentration of $O_2$ = $2.21\times 10^{-3}M$

Now put all the given values in the above expression, we get:

$\text{Rate}=(9.87\times 10^3M^{-2}s^{-1})\times (7.86\times 10^{-3}M)^2\times (2.21\times 10^{-3}M)^1$

$\text{Rate}=1.35\times 10^{-8}Ms^{-1}$

Hence, the value of rate of reaction is $1.35\times 10^{-8}Ms^{-1}$

7 0

2 years ago

200 g of solid sodium hydroxide (NaOH) are dissolved in 750 mL of water. What is the concentration of this solution?

Anastaziya [24]

Answer:

6.67 M

Explanation:

Molarity = $\frac{mol}{L}$

<em>Convert 200g NaOH to moles. Convert 750 mL to L.</em>

200 g NaOH x (1 mol/39.998 g) = 5.00025... mol NaOH

750 mL x (1 L/1000 mL) = 0.750 L

<em>Substitute values into the equation.</em>

Molarity = $\frac{5.00025}{0.750}$

Molarity = 6.667... M

Molarity = 6.67 M

8 0

2 years ago

Which of these outcomes is conclusive evidence that mixing sugar in water is a physical change

Bogdan [553]

Mixing water and sugar is a physical change. A physical change is just a change in the form of the substance, whereas a chemical change is when the substance itself changes… chemically. An easy way to figure out which is which is trying to "undo" the change. If it can be undone, it is physical.

8 0

3 years ago

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