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BaLLatris [955]
3 years ago
9

Suppose that a certain battery produces a voltage of 1.55V without a load connected (open circuit) and a current of 500mA when s

horted. According to these specifications, if we were to model this as an ideal voltage source in series with a source resistance, what should the source voltage and internal resistance be? Justify your answer
Physics
1 answer:
lubasha [3.4K]3 years ago
7 0

Answer:

Explanation:

Let the internal resistance be r .

Since in open circuit the volt is 1.55 V , this will be the source voltage .

Source voltage = 1.55

If external resistance be R .

1.55 / (R + r ) = .500

R + r = 3.1 ohm

So sum of internal resistance and external resistance will be 3.1 ohm.

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t=\frac{P}{V} =\frac{40.05*10^{6}m}{7905 m/s}=5060s=84min

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