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babunello [35]
9 months ago
6

An electric device delivers a current of 5. 0 a for 10 seconds. how many electrons flow through this device?

Physics
1 answer:
uysha [10]9 months ago
8 0

An electric device delivers a current of 5.0 A for 10 seconds then the number of electrons flowing through this device would be 3.125ₓ10²⁰

<h3>What is an electric charge?</h3>

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively). Unlike charges attract one another while like charges repel one another. We refer to an object as neutral if it has no net charge.

Electric current is defined as the charge per unit of time.

The mathematical relation between current and the electric charge

I =Q/T

where I is the current flowing

Q is the total electric charge

T is the time period for which the current is flowing

By using the above relation between electric current and electric charge

I =Q/T

By substituting the values of current and time

5 =Q/10

Q= 50 Coulomb

The charge on one electron is -1.6 ×10⁻¹⁹ coulomb.

The number of electrons = Total charge /charge on the one electron

                                         =50/1.6×10⁻¹⁹

                                          =3.125ₓ10²⁰

Thus, the total number of electrons flowing through the device would be 3.125ₓ10²⁰.

Learn more about an electric charge from here

brainly.com/question/8163163

#SPJ4

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A mass of 0.40 kg is suspended on a spring which then stretches 10 cm. The mass is then removed and a second mass is placed on t
Vanyuwa [196]

Answer:

 x' = 1.01 m

Explanation:

given,

mass suspended on the spring, m = 0.40 Kg

stretches to distance, x = 10 cm  = 0. 1 m

now,

we know

m g = k x

where k is spring constant

0.4 x 9.8 = k x 0.1

  k = 39.2 N/m

now, when second mass is attached to the spring work is equal to 20 J

work done by the spring is equal to

W = \dfrac{1}{2}kx'^2

20= \dfrac{1}{2}\times 39.2\times x'^2

 x'² = 1.0204

 x' = 1.01 m

hence, the spring is stretched to 1.01 m from the second mass.

 

7 0
3 years ago
20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What is the new vol
Alborosie
Initial volume of the gas (V1) = 10 inches^3
Initial pressure (P1) = 5 psi
Final pressure after compression of the gas (P1) = 10 psi
Let us assume the final volume of the gas (V2) = x
According to Boyle's Gas law, the pressure and volume of a gas remains constant under ideal condition. Then
P1V1= P2V2
5 * 10 = 10 * x
50 = 10x
x = 50/10
   = 5 cubic inches
So the volume of the gas after it was compressed was 5 cubic inches. I hope the procedure is clear enough for you to understand.
8 0
2 years ago
What causes an electrical current in a wire? Question 1 options: Electric fields cause atoms to move in a wire Electrons build u
Mademuasel [1]

The cause of electric current in a wire is that there is electron flow due to electrical attraction and repulsion.

What is Electric current?

The rate of flow of electric charge through a point is known as electric current. The electric current is nothing but the flow of electrons in general.

Consider a space, when electrons of charge (e) is flowing through the space in a given time interval t. Then,

I = e/t

here,

I is the electric current.

Moreover, there is a flow of electrons in a wire due to a potential difference existing at the circuit. Due to that, electrons always flow from high electric potential to low electric potential.

Thus, we can conclude that the cause of electric current in a wire is that there is electron flow due to electrical attraction and repulsion.

Learn more about the electric current here:

brainly.com/question/7643273

5 0
2 years ago
When an electron falls from a higher to a lower energy level in an atom, the photon released has a wavelength of 121.6 nm. What
yarga [219]

Answer:

\Delta E=1.64*10^{-18}J

Explanation:

The energy difference between the energy levels involved in the transition of the electron is directly proportional to the frequency of the emitted photon:

\Delta E=h\nu(1)

Where h is the Planck constant. The photon's frequency is inversely proportional to its wavelegth:

\nu=\frac{c}{\lambda}(2)

Here c is the speed of light. Replacing (2) in (1):

\Delta E=\frac{hc}{\lambda}\\\Delta E=\frac{(6.63*10^{-34}J\cdot s)(3*10^8\frac{m}{s})}{121.6*10^{-9}m}\\\Delta E=1.64*10^{-18}J

6 0
2 years ago
Use the equation d = m/v [stack fraction), where d= density, m= mass, and v
sladkih [1.3K]

Answer:

54.

Explanation:

6 (v) x 9 (m) = 54.

54 (m) / 6 (v) = 9 (d)

5 0
3 years ago
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