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babunello [35]
1 year ago
6

An electric device delivers a current of 5. 0 a for 10 seconds. how many electrons flow through this device?

Physics
1 answer:
uysha [10]1 year ago
8 0

An electric device delivers a current of 5.0 A for 10 seconds then the number of electrons flowing through this device would be 3.125ₓ10²⁰

<h3>What is an electric charge?</h3>

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively). Unlike charges attract one another while like charges repel one another. We refer to an object as neutral if it has no net charge.

Electric current is defined as the charge per unit of time.

The mathematical relation between current and the electric charge

I =Q/T

where I is the current flowing

Q is the total electric charge

T is the time period for which the current is flowing

By using the above relation between electric current and electric charge

I =Q/T

By substituting the values of current and time

5 =Q/10

Q= 50 Coulomb

The charge on one electron is -1.6 ×10⁻¹⁹ coulomb.

The number of electrons = Total charge /charge on the one electron

                                         =50/1.6×10⁻¹⁹

                                          =3.125ₓ10²⁰

Thus, the total number of electrons flowing through the device would be 3.125ₓ10²⁰.

Learn more about an electric charge from here

brainly.com/question/8163163

#SPJ4

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A5.0 kg TNT explosive, initially at rest, explodes into two pieces. One of the pieces weighing 2.0 kg flies off to
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v = 24 m/s, rightwards

Explanation:

Given that,

The mass of TBT explosive = 5 kg

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MARKING BRAINLIST | Which situation below would have the STRONGEST gravitational force between them?
maks197457 [2]

Case d) has the strongest gravitational force

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

a) For this pair of objects:

m1 = 10 kg

m2 = 2 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(2)}{30000^2}=1.48\cdot 10^{-18}N

b) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{30000^2}=7.41\cdot 10^{-18}N

c) For this pair of objects:

m1 = 2 kg

m2 = 2 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(2)(2)}{10000^2}=1.33\cdot 10^{-17}N

d) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{10000^2}=6.67\cdot 10^{-17}N

Therefore, the  strongest gravitational force is in case d).

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