Answer:
p = FΔt = 8.0 N(60 s) = 480 N•s
Explanation:
not asked for, but in that time a frictionless 18 kg mass on a horizontal surface will have change velocity by 480/18 = 26.7 m/s.
An impulse results in a change of momentum.
Answer:
Please see below as the answers are self-explanatory
Explanation:
a)
- A electric field line is an imaginary line, which has the property that the electric field vector is tangent to it at any point. It starts from positive charges (since the electric field by convention it has the direction of the trajectory that would take a positive test charge, so it always goes away from positive charges) and ends in negative charges.
b)
- Since the potential difference between two points represents the work per unit charge needed for a charge to move between these points, a equipotential surface is the one over which it is not needed to do work to move a charge from any point on the surface to any other point, which means that all points are at the same potential.
c)
- Equipotential surfaces are not necessarily physical surfaces, they can be defined in vaccum for instance.
- As an example, any spherical surface concentric with a point charge, is an equipotential surface, and it can be a real surface or a fictitious one.
Answer:
9.43 m/s
Explanation:
First of all, we calculate the final kinetic energy of the car.
According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:
where
W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)
is the final kinetic energy
is the initial kinetic energy
Solving,
Now we can find the final speed of the car by using the formula for kinetic energy
where
m = 661 kg is the mass of the car
v is its final speed
Solving for v, we find
The answer is it will supply 1.1 x 10⁹ J of energy each second.
we can calculate this by using the following equation;
P = W/t
<span>W = P x t
</span><span>and by work energy relation;
E = W = P x t
</span>1 watt = 1j/s
1megawatt = 1000000 = 10⁶ j/s
<span>E = 1100 x 106 x 1 </span>
E = 1.1 x 10⁹ J
