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lisabon 2012 [21]
2 years ago
11

Hold a spoon such that the water will hit the back of the spoon. The handle of the spoon will be horizontal. Turn on the water,

but not full strength though.
Physics
1 answer:
antoniya [11.8K]2 years ago
6 0

This is an experiment that explains the Bernoulli principle. According to this principle, at the bottom of the spoon, there will be a reduction in pressure.

<h3>Explanation of the Bernoulli principle</h3>

So the pressure at the bottom of the spoon reduces because the velocity of the water is larger and the height of the column of water is smaller at this part.

So the spoon is attracted to the water at the point of lowest pressure because objects gravitate to low-pressure points.

Learn more about the Bernoulli Principle at:

brainly.com/question/24623919

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A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the
Novay_Z [31]

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

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4 0
3 years ago
What percentage of the original kinetic energy is convertible to internal energy?
schepotkina [342]
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7 0
3 years ago
You wad up a piece of paper and throw it into the wastebasket. How far will
vitfil [10]

The range of the piece of paper is C) 1.4 m

Explanation:

The motion of the piece of paper is the motion of a projectile, which consists of two separate motions:

- A uniform motion along the horizontal direction, with constant velocity

- A uniformly accelerated motion along the vertical direction, with constant acceleration (the acceleration of gravity, g=9.8 m/s^2)

From the equation of motion, it is possible to find an expression for the range (the total horizontal distance covered) of a projectile, which is given by:

d=\frac{u^2 sin 2\theta}{g}

where

u is the initial velocity

\theta is the angle of projection

g is the acceleration of gravity

For the piece of paper in this problem,

u = 4.3 m/s

\theta=65^{\circ}

Substituting,

d=\frac{(4.3)^2 sin(2\cdot 65^{\circ})}{9.8}=1.45 m \sim 1.4 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
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