Answer:
419.25 lbs
Explanation:
Let iron density be 491.5 lb/ft3
and aluminum density be 169 lb/ft3
We can calculate the mass of iron that displaces 1.3ft3
Also the mass of aluminum that displaces 1.3 ft3
So by using aluminum, the airplane can save
638.95 - 219.7 = 419.25 lbs of weight
The force that is pushing the crate up the ramp is competing with at least another two forces, those being G force= defines the attraction to the earth and Ff, the friction between the crate and the rough material of the ramp
Any Force can be defined by the weigh of a particular body and the acceleration
the kinetic friction indicative would be defined by the report between the active force and the friction force, considering G
So 5000-22%×5000=250× a
a=3900/250 m/s
Answer:
(a) work required to lift the object is 1029 J
(b) the gravitational potential energy gained by this object is 1029 J
Explanation:
Given;
mass of the object, m = 35 kg
height through which the object was lifted, h = 3 m
(a) work required to lift the object
W = F x d
W = (mg) x h
W = 35 x 9.8 x 3
W = 1029 J
(b) the gravitational potential energy gained by this object is calculated as;
ΔP.E = Pf - Pi
where;
Pi is the initial gravitational potential energy, at initial height (hi = 0)
ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)
ΔP.E = 1029 J
Answer
given,
initial speed of the car (v₁)= 19.8 mi/h
final speed of the car (v₂)= 59.9 mi/h
a) initial momentum = m v₁
P₁ = 19.8 m
final final momentum = m v₂
P₂ = 59.9 m
ratio =
=
ratio of momentum=
b) initial kinetic energy= 1/2 m v₁²
K₁ = 196.02 m
final kinetic energy= 1/2 m v₂²
K₂ = 1794.005 m
ratio =
=
ratio of Kinetic energy=