David measured the height of a window frame as 5.61 feet, but the actual height was 6 feet. What is the percentage of error in D

Question

DaniilM [7]

3 years ago

14

David measured the height of a window frame as 5.61 feet, but the actual height was 6 feet. What is the percentage of error in D

avid's measurement?

Mathematics

1 answer:

Nataly [62] · Answer 1 · 2021-12-06T11:03:04+03:00

<h2>Percentage of error in David's measurement is 6.5 %</h2>

Step-by-step explanation:

Measured height = 5.61 feet

Original height = 6 feet

Error in measurement = Original height - Measured height

Error in measurement = 6 - 5.61

Error in measurement = 0.39 feet

$\texttt{Percentage of error in David's measurement = }\frac{\texttt{Error in measurement}}{\texttt{Original height}}\times 100\\\\\texttt{Percentage of error in David's measurement = }\frac{0.39}{6}\times 100\\\\\texttt{Percentage of error in David's measurement = }6.5\%$

Percentage of error in David's measurement is 6.5 %