Answer:
²³⁰₉₀Th
Explanation:
X → ²²⁶₈₈Ra + ⁴₂He
The given equation shows the alpha emission. When He particle emit the original atom convert into the atom having mass number less than 4 and atomic number less than 2 as compared to parent atom the starting atom. It means the parent atom is ²³⁰₉₀Th.
Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4 and atomic number less than 2 as compared to parent atom the starting atom.
Alpha radiations can travel in a short distance.
These radiations can not penetrate into the skin or clothes.
These radiations can be harmful for the human if these are inhaled.
These radiations can be stopped by a piece of paper.
₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴ + energy
Answer: The atomic mass of these two isotopes is 40.03 amu. The average mass is closer to actual amu of 58.69 for nickel as its percentage abundance is more.
Explanation:
Mass of isotope 1 = 63.93
% abundance of isotope 1 = 0.93% =
Mass of isotope 2 = 57.93
% abundance of isotope 2 = (68.08)% =
Formula used for average atomic mass of an element :
Therefore, the average atomic mass of nickel is, 40.03 amu. The average mass is closer to actual amu of 58.69 for nickel as its percentage abundance is more.
Answer:
269.068 kJ/mol.
Explanation:
<em>ln (k₂/k₁) = (Eₐ/R) [(T₂ - T₁)/(T₁T₂)].</em>
<em>k₁ = 6.20 x 10⁻⁴ min⁻¹, T₁ = 700.0 K.</em>
<u><em>To get k₂:</em></u>
in first order reactions: k = 0.693/(half-life).
∴ k₂ = 0.693/(29.0 min) = 2.39 x 10⁻² min⁻¹, T₂ = 760.0 K.
∵ ln (k₂/k₁) = (Eₐ/R) [(T₂ - T₁)/(T₁T₂)]
∴ ln [(2.39 x 10⁻² min⁻¹)/(6.20 x 10⁻⁴ min⁻¹)] = (Eₐ/(8.314 J/mol.K)) [(760.0 K - 700.0 K) / (760.0 K)(700.0 K)].
3.65 = (Eₐ/(8.314 J/mol.K)) (1.128 x 10⁻⁴).
<em>∴ Eₐ =</em> (3.65)(8.314 J/mol.K) / (1.128 x 10⁻⁴) = <em>269.068 kJ/mol.</em>
Answer:
Product: propan-1-ol
Explanation:
IIn this case, we have to remember that is a reduction agent. So, this is a <u>reduction reaction</u>. The has the ability to produce <u>hydride ions </u>. This ion can attack the <u>carbonyl group</u> generating a negative charge in the oxygen. In the next step, the negative charge in the oxygen can attack a water molecule to<u> protonate</u> the molecule and produce <u>propan-1-ol</u>.
See figure 1
I hope it helps!
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