Answer:
0.2788 M
1.674 %(m/V)
Explanation:
Step 1: Write the balanced equation
NaOH + CH₃COOH → CH₃COONa + H₂O
Step 2: Calculate the reacting moles of NaOH
Step 3: Calculate the reacting moles of CH₃COOH
The molar ratio of NaOH to CH₃COOH is 1:1.
Step 4: Calculate the molarity of the acetic acid solution
Step 5: Calculate the mass of acetic acid
The molar mass of acetic acid is 60.05 g/mol.
Step 6: Calculate the percentage of acetic acid in the solution
Answer:
The likely causes inferred about the differences in times observed are;
1) Slight increase of the vapor pressure of the air immediately above the water surface due to the presence of a lid
2) Variation of heat input due to wind draft that alters the focus of the flame
3) The introduction of impurities into the water from the water source or through the sourcing mediums or containers or during handling of the water
Explanation:
The factors that affect the boiling point of water includes;
1) The amount of heat supplied, to the water
2) Vapor pressure above the water surface
3) Presence of impurities in the water
Therefore, the most likely causes for the difference in the times observed for the water to boil in the order of increasing probability of cause and effect are therefore;
1) Slight increase of the vapor pressure of the air immediately above the water surface due to the presence of a lid
2) Variation of heat input due to wind draft that alters the focus of the flame
3) The introduction of impurities into the water from the water source or through the sourcing mediums or containers or during handling of the water.
<span>The 80 ml solution has (.04)(80) ml of the medicine, or 3.3 ml of medicine.The pharmacist adds V ml of 7% solution, or .07V ml of medicine. The total amoune of medicine is (.07V + 3.2) mg.
The total volume of solution is (V + 80) ml, so
(.07V + 3.2) / (V + 80) = .05. Solve for V.</span>
Answer:
STP conditions imply a temperature of 273.15 K and a pressure of 100 kPa. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. Likewise, 0.5 moles will occupy half the volume 1 mole occupies. Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies 22.4 L . This means the number of moles of O2 is 222.4=0.089 mol .
Explanation:
