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Yuri [45]
3 years ago
5

Methanol can be synthesized by combining carbon monoxide and hydrogen. CO(g) 2H2(g) CH3OH(g) . A reaction vessel contains the th

ree gases at equilibrium with a total pressure of 1.00 atm. What will happen to the partial pressure of hydrogen if enough argon is added to raise the total pressure to 1.4 atm?A.The partial pressure of hydrogen will decrease
B. The partial pressure of hydrogen will increase
C. The partial pressure of hydrogen will be unchanged
D. Kp needs to be known before a prediction can be made
E. Both Kp and the temperature need to be known before a prediction can be made
Chemistry
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

The answer is C. The partial pressure of hydrogen will be unchanged.

Explanation:

CO_{(g)} + 2H_{2(g)}  ⇒  CH_{3}OH

Argon with electronic configuration 1s^{2}  2s^{2}  2p^{6}  3s^{2}  3p^{6} (that is atomic number 18) is an inert gas making it unreactive and it's addition to the reaction has no effect on the partial pressure of either the reactant or production or the state of the system.

The partial pressure of hydrogen will remain unchanged on the addition of Argon.

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Answer:

i would say the anwser is C

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Enthalpy of <br><br> CH4(g) + 2NO2(g) -&gt; N2(g) + CO2(g) + 2H2O(l)
stira [4]

Answer:

-177.9 kJ.

Explanation:

Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.

5 0
3 years ago
A chemistry student weighs out of hypochlorous acid into a volumetric flask and dilutes to the mark with distilled water. He pla
riadik2000 [5.3K]

Answer:

<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>

A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.

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Concentration = no. of moles/volume in L

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= 0.005M.

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Answer:

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