Syntax
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Answer: Clogged EGR ports or passages
Explanation: The clogging causes insufficient flow.
Answer:
The statement regarding the mass rate of flow is mathematically represented as follows
Explanation:
A junction of 3 pipes with indicated mass rates of flow is indicated in the attached figure
As a basic sense of intuition we know that the mass of the water that is in the pipe junction at any instant of time is conserved as the junction does not accumulate any mass.
The above statement can be mathematically written as
this is known as equation of conservation of mass / Equation of continuity.
Now we know that in a time 't' the volume that enter's the Junction 'O' is
1) From pipe 1 =
1) From pipe 2 =
Mass leaving the junction 'O' in the same time equals
From pipe 3 =
From the basic relation of density, volume and mass we have
Using the above relations in our basic equation of continuity we obtain
Thus the mass flow rate equation becomes
Answer:
Given data:
Equation of the state
Where p = pressure of fluid, pα
T = Temperature of fluid, k
V = Specific volume of fluid
R = gas constant ,
a, b = Constants
Solution:
Specific heat difference,
According to cyclic reaction
Hence specific heat difference is
Equation of state,
Differentiating the equation of state with respect to temperature at constant volume,
Differentiating the equation of the state with respect to volume at constant temperature.
Substituting both eq (3) and eq (4) in eq (2)
We get,
Specific heat difference equation,
Answer:
rate of heat transfer = 9085708.80 W
Explanation:
Given:
Inside diameter, D = 5.1 cm
= 5.1 x m
Average velocity, V = 7 m/s
Mean temperature, T = (66+38) /2
= 52°C
Therefore kinematic viscosity at 52°C is ν = 0.104 X / s
Prandtl no., Pr = 0.021
We know Renold No. is
Re =
Re =
= 3.432 X
Therefore the flow is turbulent.
Since the flow is turbulent and the ratio of L/D is greater than 60 we can use Dittua-Boelter equation.
Nu = 0.023 .
= 0.023 x x
= 1221.52
Since Nu =
h =
=
= 225143.3
Therefore rate of heat transfer, q = h.A(T-
q= 225143.3 x 2πrh ( 66-38)
= 225143.3 X 2π X
= 9085708.80 W