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3 years ago

Help Please!!!!!!! Whatever3443 Please help!

Engineering

2 answers:

KIM [24]3 years ago

8 0

Answer:

Thanks for the pointssssssssssssss

Explanation:

Olin [163]3 years ago

7 0

Answer:

I need some help understanding this question what is it you need to know about doc. whatever 3443?

744 with 3040 1230 0 215 141 184 247 353 whatever 3443 1230 0 215 140 246 337 400 492 581 673 737 for 4232 1230 0 215 50 154 218 which 4499 1230

Explanation:

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A 450 MWt combined cycle plant has a Brayton cycle efficiency of 24% and a Rankine cycle efficiency of 29% with no heat augmenta

Romashka-Z-Leto [24]

Answer:

Output of plant=207.18 MW

Explanation:

Given input energy Q=450 MW

Brayton cycle efficiency $\eta_1=24$ %

Rankine cycle efficiency $\eta_2=29$ %

Combined efficiency for two cycle given as follow

$\eta _b=\eta _1+\eta _2-\eta _1\eta _2$

$\eta _b=0.24+0.29-0.24\times 0.29$

$\eta_b=0.4604$

We know that efficiency $\eta =\dfrac{out\ put}{in\ put}$

out put of plant= $450\times 0.4604$

So output of plant=207.18 MW

4 0

3 years ago

Which of these credit building options do you personally think is the easiest method that you can see yourself doing? Explain yo

enot [183]

Answer:

Explanation:

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7 0

3 years ago

Why are you asked to draw a sketch of a Bridge-Design on a graph sheet/A4 sheet?

elena-s [515]

Engineers or architects can be asked to draw a sketch of a bridge-design on a graph sheet or A4 paper to communicate their ideas and scale their drawings.

Architectural sketches are about the communication of ideas. Engineers and architects use hand sketching to clarify elements of the design to the contractor or client.

It should be noted that drawings can also be drawn on a graph sheet or A4 paper to represent the detail before it's eventually constructed.

Scale drawings are used for the illustration of items that are not convenient to draw their actual size. In the construction industry, scales are used depending on the nature of the drawing. Drawings can be made on a graph or A4 paper due to the ease of printing, reproducing, and resizing the drawings.

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brainly.com/question/20689874

4 0

2 years ago

Read 2 more answers

Q1) Determine the force in each member of the

Sever21 [200]

Answer:

CD = DE = DF = 0
BC = CE = 15 N tension
FA = 15 N compression
CF = 15√2 N compression
BF = 25 N tension
BG = 55/2 N tension
AB = (25√5)/2 N compression

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The <em>horizontal</em> forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

(25√5)/2 N compression in AB
15 N tension in BC
25 N tension in BF
0 N in CD, DE, and EF
15 N tension in CE
15√2 compression in CF
15 N compression in FA

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

8 0

3 years ago

"How would you direct traffic in the result of a catastrophic earthquake?"

11Alexandr11 [23.1K]

Answer:

In the result of a earthquake, you should direct people into areas that are safe, such as places where the ground has not been broken up, and then tell people to get out of their cars and be careful. You should also have them carry any valuable items out of the car(if they have time), and then wait until the initial shocks and aftershocks are over, and then tell them to get back into their cars and then drive carefully and safely.

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3 years ago

Read 2 more answers