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hram777 [196]
3 years ago
12

A coin placed 30.8 cm from the center of a rotating, horizontal turntable slips when its speed is 50.8 cm/s.

Engineering
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

a)(A) static friction

b)\mu _s=0.085

Explanation:

Given that

r = 30.8 cm

V = 50.8 cm/s

a)

(A) static friction

b)

At the condition of motion

Static friction = Centrifugal force

\mu _s\ m\ g=\dfrac{mV^2}{r}

\mu _s\ g=\dfrac{V^2}{r}

\mu _s\times 980=\dfrac{50.8^2}{30.8}

\mu _s=0.085

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marin [14]

Answer:1.)envirmental protection agency(EPA)

2.)lens shade number

3.)source extraction ventalation

4.)personal safety/protective equipment

Explanation:

4 0
3 years ago
Consider a plane composite wall that is composed of two materials of thermal conductivities kA = 0.1 W/m*K and kB = 0.04 W/m*K a
nadya68 [22]

Answer:

q=39.15 W/m²

Explanation:

We know that

Thermal resistance due to conductivity given as

R=L/KA

Thermal resistance due to heat transfer coefficient given as

R=1/hA

Total thermal resistance

R_{th}=\dfrac{L_A}{AK_A}+\dfrac{L_B}{AK_B}+\dfrac{1}{Ah_1}+\dfrac{1}{Ah_2}+\dfrac{1}{Ah_3}

Now by putting the values

R_{th}=\dfrac{0.01}{0.1A}+\dfrac{0.02}{0.04A}+\dfrac{1}{10A}+\dfrac{1}{20A}+\dfrac{1}{0.3A}

R_{th}=4.083/A\ K/W

We know that

Q=ΔT/R

Q=\dfrac{\Delta T}{R_{th}}

Q=A\times \dfrac{200-40}{4.086}

So heat transfer per unit volume is 39.15 W/m²

q=39.15 W/m²

4 0
3 years ago
Determine the dimensions for W if W = P L^3 / (M V^2) where P is a pressure, L is a length, M is a mass, and V is a velocity.
Eva8 [605]

Correct answer is option E. No dimensions

As we know formula Pressure (P) is \frac{F}{A}

also,

  • Dimensional formula of <em>Pressure is </em>M^{1}L^{-1}T^{-2}
  • Dimensional formula of <em>length is L </em>
  • Dimensional formula of <em>mass is M</em>
  • Dimensional formula  of <em>velocity is </em>L^{1} T^{-1}

So, as given W=\frac{P*L^{3} }{M*V^{2} }

Dimensional formula of W =\frac{M^{1}L^{-1}T^{-2}  L^{3}  }{M^{1} L^{2}T^{-2}   }

since all terms get cancelled

Work is dimensionless i.e no dimensions

Learn more about dimensions here brainly.com/question/20351712

#SPJ10

6 0
2 years ago
A hydraulic cylinder is to be used to move a workpiece in a manufacturing operation through a distance of 50 mm in 10 s. A force
svetlana [45]

Answer:

The answer to this question is 1273885.3 ∅

Explanation:

<em>The first step is to determine the required  hydraulic flow rate liquid if working pressure and  if a cylinder with a piston diameter of 100 mm is available.</em>

<em>Given that,</em>

<em>The distance = 50mm</em>

<em>The time t =10 seconds</em>

<em>The force F = 10kN</em>

<em>The piston diameter is = 100mm</em>

<em>The pressure = F/A</em>

<em> 10 * 10^3/Δ/Δ </em>

<em> P = 1273885.3503 pa</em>

<em>Then</em>

<em>Power = work/time  = Force * distance /time</em>

<em> = 10 * 1000 * 0.050/10</em>

<em>which is  =50 watt</em>

<em>Power =∅ΔP</em>

<em>50 = 1273885.3 ∅</em>

5 0
3 years ago
1.8 A water flow of 4.5 slug/s at 60 F enters the condenser of steam turbine and leaves at 140 F. Determine the heat transfer ra
Ann [662]

Answer:

Hr=4.2*10^7\ btu/hr

Explanation:

From the question we are told that:

Water flow Rate R=4.5slug/s=144.78ib/sec

Initial Temperature T_1=60 \textdegree F

Final Temperature  T_2=140 \textdegree F

Let

Specific heat of water \gamma= 1

And

 \triangle T= 140-60

 \triangle T= 80\ Deg.F

Generally the equation for Heat transfer rate of water  H_r is mathematically given by

Heat transfer rate to water= mass flow rate* specific heat* change in temperature

 H_r=R* \gamma*\triangle T

 H_r=144.78*80*1

 H_r=11582.4\ btu/sec

Therefore

 H_r=11582.4\ btu/sec*3600

 Hr=4.2*10^7\  btu/hr

3 0
3 years ago
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