Question

A coin placed 30.8 cm from the center of a rotating, horizontal turntable slips when its speed is 50.8 cm/s.

Answer 1

Answer:

a)(A) static friction

b)$\mu _s=0.085$

Explanation:

Given that

r = 30.8 cm

V = 50.8 cm/s

a)

(A) static friction

b)

At the condition of motion

Static friction = Centrifugal force

$\mu _s\ m\ g=\dfrac{mV^2}{r}$

$\mu _s\ g=\dfrac{V^2}{r}$

$\mu _s\times 980=\dfrac{50.8^2}{30.8}$

$\mu _s=0.085$