Answer: Wax
Explanation:
Density is defined as the mass contained per unit volume.

Usually solids are more denser than liquid, as molecules in solid are more strongly packed and thus have more mass per unit volume.
Liquids on the other hand contain molecules which are less tightly bound and thus thus contain less mass per unit volume as compared to solid.
Example: Solid wax is more denser than liquid wax.
Answer:
the correct option is D.
Explanation:
ionic bond:
ionic bond is a bond where one of the atom donates one or two electron to one or more than one atom for all the atom to attain stability that is octet.
chlorine has 17 electrons so the outer most orbit has 7 electron for it to obtain stability it has to gain one more electron while magnesium has 12 electrons so it has to lose 2 electrons to gain stability so if a magnesium atom loses 2 of its electron to two chlorine atoms botn the chlorine will have 18 electron and magnesium will have 10 electron therefore every atom attaining octet. by this way magnesium forms ionic bond with two chlorine atom to form MgCl2.
so option d must be correct.
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>
Given
80% 127I, 17% 126I, and 3% 128I.
Required
The average atomic mass
Solution
The elements in nature have several types of isotopes
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%
Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128
Atomic mass of Iodine = 101.6 + 21.42 + 3.84
Atomic mass of Iodine = 126.86 amu
Answer:
Approximately 2000 J.
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- <em>q</em> is heat (in J)
- <em>m</em> is mass (in g)
- <em>c</em> is specific heat (in J/g °C)
- ΔT is change in temperature (in °C or K)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>c</em> = 0.897 J/g °C
[Given] <em>m</em> = 79 g
[Given] ΔT = 28°C
[Solve] <em>q</em>
<em />
<u>Step 2: Solve for </u><em><u>q</u></em>
- Substitute in variables [Specific Heat Formula]: q = (79 g)(0.897 J/g °C)(28 °C)
- Multiply [Cancel out units]: q = (70.863 J/°C)(28 °C)
- Multiply [Cancel out units]: q = 1984.16 J
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>
1984.16 J ≈ 2000 J