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3 years ago

Which term is used to describe a group of arctic foxes that live in part of Alaska’s Arctic National Wildlife Refuge?

Chemistry

2 answers:

Allushta [10]3 years ago

7 0

Answer:

The best answer would be biome

serious [3.7K]3 years ago

4 0

Answer:

<u><em>Population would be the answer</em></u>

Explanation:

Population is the term that is used to describe a group of arctic foxes that live in part of Alaska's Arctic National Wildlife Refuge. The correct option among all the options given in the question is the third or the second last option. The area covered by Arctic National Refuge is approximately 19.6 million acres. It has a variety of wild animals living in it.

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Which orbital is partially filled in the Zirconium (ZI) atom?

Nikolay [14]

Answer:

4d orbital.

Explanation:

Hello!

In this case, since zirconium's atomic number is 40, we fill in the electron configuration up to 40 as shown below:

$1s^2,2s^2,2p^6, 3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^2$

Thus, the orbital 4d is partially filled.

Best regards!

3 0

3 years ago

What is the name of the average weather in an area over a long period of time?

Nezavi [6.7K]

Climate is the weather that occur over a long period in a particular place.

3 0

3 years ago

How many grams of aluminum oxide (Al2O3) will be formed from 10.0 grams of aluminum (Al)? 4 AL + 3 02 --> 2 AL203

d1i1m1o1n [39]

Answer:

Mass = 18.9 g

Explanation:

Given data:

Mass of Al₂O₃ formed = ?

Mass of Al = 10.0 g

Solution:

Chemical equation:

4Al + 3O₂ → 2Al₂O₃

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 27 g/mol

Number of moles = 0.37 mol

Now we will compare the moles of Al and Al₂O₃.

Al : Al₂O₃

4 : 2

0.37 : 2/4×0.37 = 0.185 mol

Mass of Al₂O₃:

Mass = number of moles × molar mass

Mass = 0.185 mol × 101.9 g/mol

Mass = 18.9 g

4 0

2 years ago

How many kj of heat are needed to completely vaporize 1.30 moles of h2o? the heat of vaporization for water at the boiling point

Cerrena [4.2K]

The Kj of heat that are needed to completely vaporize 1.30 moles of H2O if the heat of vaporization for water is 40.6 Kj/mole is calculated as below

Q(heat) = moles x heat of vaporization)

=1.30 mol x40.6 kj/mol= 52.78 Kj is needed

6 0

3 years ago

Read 2 more answers

How many grams are in 44.8 liters of nitrogen gas, n2?<br> a) 56g<br> b) 27g<br> c) 36g<br> d) 112g

kkurt [141]

a) 56g

<h3>Calculation:</h3>

At STP,

22.4 L of N₂ = 1 mol

We have given 44.8 L of N₂, therefore,

44.8 L of N₂ = $\frac{44.8}{22.4}$