Answer:
B
Explanation:
OOf we are doing this stuff atm
So if its faster at the front and slow at the back you can tell that its not slowing down because less of a force is there however at the front there is more of a force. Friction is low which means that its not makimg much contact so no sudden change of forces thats also why its B
Answer: h = 0.52m
Explanation:
Using the equation of out flow;
A1 × V1 = A2 ×V2
Where A1 = area of the first nozzle
A2 = area of the second nozzle
V1= velocity of flow out from the first nozzle
V2 = velocity of flow out from 2nd nozzle
But AV= area of nozzle × velocity of water = volume of water per second(m³/s).
Now we can set A×V = Area of nozzle × height of rise.
Henceb A1× h1 = A2 × h2 ( note the time cancel on both sides)
D1 = 20mm= 0.02m; h1 = 0.13m
D2 = 10mm = 0.01m; h2= ?
h2 = π(D1/2)²× h1 /π(D2/2)²
h2 = (0.02/2)² × 0.13/(0.01/2)²
= (0.01)² ×0.13 /(0.005)²
= 1.3 × 10^-5/(5 × 10^-3)²
= 1.3 × 10^-5/25 × 10^-6
= (1.3/25) 10^-5 × 10^6
= 0.052× 10
= 0.52m
The mass of one cubic meter of water in kilograms is 1 kg.
This is a conversions case. First, we must determine how many cubic centimeters there are in a cubic meter. We have 1000 of these after conversion.
This essentially indicates that 1000 units of water, each with a volume of one cubic centimeter, would have to combine before we could create a cubic meter of water.
Knowing that one cubic centimeter weighs one gram, 1000 cubic centimeters would weigh 1000 * 1, or 1000g, or one kilogram.
Thus, 1 cubic meters of water will weigh 1 * 1000g = 1000g, or just 1 kg.
Learn more about the Measurement of mass with the help of the given link:
brainly.com/question/13730160
#SPJ4
Answer:
3 m/s
Explanation:
average speed = distance traveled / total time taken
= 6m/ 2s
= 3 m/s
The right answer for the question that is being asked and shown above is that: "d. As the distance from the Earth increases, the sound wave intensity also decreases due to the lessening density." This the <span>statement that is untrue in regard to sound traveling in air</span>
