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Sonja [21]
2 years ago
13

The energy efficiency of a car is approximately 20%. If you put 10 gallons of gas into the car, how many gallons are “wasted”?

Physics
1 answer:
podryga [215]2 years ago
4 0
First, you find what 20% of 10 gallons of gas would be. This will show how many gallons the car actually uses.
10 gallons x 20% =
10 x 0.20 =
2 gallons used

Then you subtract that number from the total 10 gallons to get how many gallons of gas would be wasted.
10 gallons - 2 gallons = 
8 gallons of gas wasted
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Bart stole a watermelon and ran 5,000 feet from the cops and they chase lasted 0.1 hours how fast was Bart running in miles per
liraira [26]
I am not as sure but I think it is 9.469 miles
5 0
2 years ago
- A fridge has a maximum static friction force
Dennis_Churaev [7]

Answer:

They will move the fridge if they all push in the same direction, but it will not move with constant velocity

Explanation:

The maximum static friction force is

F_f = -250 N (negative sign since its direction is opposite to the push applied by the people)

Sam can apply a force of 130 N, while Amir and Andre can apply a push of 65 N each, so the total force that they can apply, if they push in the same direction, will be:

F=130 + 65 +65=260 N

This force is larger than the frictional force, so the fridge will start moving.

However, the net force on the fridge will be:

\sum F = 260 N - 250 N = 10 N

And according to Newton's second law,

\sum F = ma

where m is the mass of the fridge and a its acceleration, since the net force is not zero, then the fridge will have a non-zero acceleration, so it will not move with constant  velocity.

3 0
3 years ago
How many watt hours will 3-155amp hour 12 volt batteries wired in a parallel configuration produce?
Ede4ka [16]

Answer:

B 5580 W•hr

Explanation:

A Watt is a Volt times an Amp

3(12 V(155 A•hr)) = 5580 W•hr

4 0
2 years ago
Suppose the roller coaster in Fig. 6-38 (h1 = 33 m, h2 = 13 m, h3 = 25) passes point A with a speed of 2.10 m/s. If the average
Kamila [148]

Answer:

22.67 m/s

Explanation:

See in the picture.

7 0
3 years ago
The main water line enters a house on the first floor. The line has a gauge pressure of 2.10 x 105 Pa. (a) A faucet on the secon
Eva8 [605]

To answer this question is necessary to apply the concepts related to Bernoulli's equation. The Bernoulli-related concept describes the behavior of a liquid moving along a streamline. Pressure can be defined as the proportional ratio between height, density and gravity:

P = h\rho g

Where,

h = Height

\rho = Density

g = Gravity

Our values are

\rho = 1000kg/m^3 \rightarow density of water at normal conditions

h = 7.3m

g = 9.8m/s^2

PART A) Replacing these values to find the total pressure difference we have to

P_1 = h_1 \rho g

P_1 = (7.3)(1000)(9.8)

P_1 = 71540Pa

In this way the pressure change would be subject to

\Delta = P_2-P_1

\Delta = 2.1*10^5Pa- 0.7154*10^5Pa

\Delta = 138460Pa

\Delta = 0.135Mpa

PART B) Considering the pressure gauge of the group as the ideal so that at a height H the water cannot flow even if it is open we have to,

P_2 = H\rho g

2.1*10^5 = H (1000)(9.8)

H = 21.42m

Therefore the high which could a faucet be before no water would flow from it is 21.42m

5 0
3 years ago
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