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3 years ago

If your runnin at full speed for an average human, and lept over a 10 foot brook would you make it?

2 answers:

7 0

Unless you are a mutant....I don't think you would make it. I'm 5'8" and most people are 6'7" or less. It's bsically impossible to do. :)

LiRa [457]3 years ago

6 0

This seems a bit too trivial for this site but I'll bite anyways. An average speed for a human would be around 8 mph, so running would probably be around 12 mph. The longest long jump ever is 26 feet, but the average is <span>7' 3" to 7' 6.5", which is quite far away from the 10 ft brook. Therefore nope!</span>

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Adding energy or increasing the speed of the particles at very low pressure in a solid would cause

weqwewe [10]

D. sublimation is correct

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3 years ago

cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your

sp2606 [1]

We have that the time in seconds, minutes, and hours is

$t=1.083*10^{-4}s$

$T_{min}=1.805*10^{-6}min$

$T_{hours}=3.0083*10^{-8}hours$

From the Question we are told that

Velocity $v=13.0m/s$

Distance $d=120 km$

Generally the equation for the Time is mathematically given as

$t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s$

Therefore

$T_{min}=1.083*10^{-4}s/60$

$T_{min}=1.805*10^{-6}min$

And

$T_{hours}=T_{min}/60$

$T_{hours}=3.0083*10^{-8}hours$

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3 years ago

A horse began running due east and covered 25 km in 4.0 hr. What is the average velocity of the horse?

Darina [25.2K]

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4 years ago

Read 2 more answers

The first and second coils have the same length, and the third and fourth coils have the same length. They differ only in the cr

stealth61 [152]

Answer:

$\frac{R_2}{R_1}=\frac{A_1}{A_2}\\\frac{R_4}{R_3}=\frac{A_3}{A_4}$

Explanation:

The resistance of a conductor is directly proportional to its length and is inversely proportional to its cross-sectional area, this dependence is given by:

$R=\frac{\rho L}{A}$