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algol13
3 years ago
8

Where are some of Earth's youngest rocks found?

Physics
1 answer:
Over [174]3 years ago
4 0
No the answer is C at the seafloor spreading centers
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Two forces act on a 1250 kg sailboat as it moves through the water with an initial velocity of 11 m/s. The forward force of the
Naddik [55]

Answer:

The velocity of the boat 15 seconds later is 5.6 meters per second.

Explanation:

We assume that sailboat can be modelled as particle, so that we use solely translations equations. It is noticed that the sailboat is move by action of the wind and drag force of the water is opposed to such force, but the last force has a greater magnitude than the first one, meaning that net force is less than zero.

From Newton's Laws we have the following equation of equilibrium for the sailboat:

\Sigma F = F - f = m\cdot a (Eq. 1)

Where:

F - Force from the wind exerted on the sailboat, measured in newtons.

f - Drag force of the water, measured in newtons.

m - Mass of the sailboat, measured in kilograms.

a - Net acceleration of the sailboat, measured in meters per square second.

If we know that F = 3.90\times 10^{3}\,N, f = 4.35\times 10^{3}\,N and m = 1250\,kg, then the net acceleration of the sailboat is:

a = \frac{F-f}{m}

a = \frac{3.90\times 10^{3}\,N-4.35\times 10^{3}\,N}{1250\,kg}

a = -\frac{9}{25}\,\frac{m}{s^{2}}

If sailboat decelerates uniformly, then we can get the final velocity of the boat by using this equation of motion:

v = v_{o}+a\cdot t (Eq. 2)

Where:

v_{o}, v - Initial and final velocities of the sailboat, measured in meters per second.

t - Time, measured in seconds.

If we get that v_{o} = 11\,\frac{m}{s}, a = -\frac{9}{25}\,\frac{m}{s^{2}} and t = 15\,s, then the final velocity of the sailboat is:

v = 11\,\frac{m}{s} +\left(-\frac{9}{25}\,\frac{m}{s^{2}}  \right)\cdot (15\,s)

v = 5.6\,\frac{m}{s}

The velocity of the boat 15 seconds later is 5.6 meters per second.

3 0
3 years ago
How do lone pairs of electrons affect the bond angle differently than electrons shared in a bond?
lubasha [3.4K]

Answer:

Lone pairs cause bond angles to deviate away from the ideal bond angles

Explanation:

Bonded electrons are stabilized and clustered between the bonding electrons meaning they are much closer together. Non-bonding electrons however are not being shared between any atoms which allows them to roam a little further spreading the charge density over a larger space and therefore interfering with what would be an expected bond angle

3 0
2 years ago
Two condition required for work done​
mixas84 [53]
1) There must be a force
2) There must be displacement
5 0
2 years ago
How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?
slega [8]

The time the truck must apply the given force to increase its speed to given value is 5 s.

The given parameters;

  • <em>applied force, F = 600 N</em>
  • <em>mass of the truck, m = 1,500 kg</em>
  • <em>speed of the truck, v = 2 m/s</em>

The force applied to the truck is determined by Newton's second law of motion; <em>which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.</em>

F = ma

F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s

Thus, the time the truck must apply the given force to increase its speed to given value is 5 s.

Learn more here:brainly.com/question/1988795

7 0
2 years ago
Two loudspeakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from the other. (a) What is the lowest fre
VMariaS [17]

Answer:

Explanation:

Given

Distance between two loud speakers d=1.6\ m

Distance of person from one speaker x_1=3\ m

Distance of person from second speaker x_2=3.5\ m

Path difference between the waves is given by

x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}

for destructive interference m=0 I.e.

x_2-x_1=\frac{\lambda }{2}

3.5-3=\frac{\lambda }{2}

\lambda =0.5\times 2

\lambda =1\ m

frequency is given by

f=\frac{v}{\lambda }

where v=velocity\ of\ sound\ (v=343\ m/s)

f=\frac{343}{1}=343\ Hz

For next frequency which will cause destructive interference is

i.e. m=1 and m=2

3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda

\lambda =\frac{1}{3}\ m

frequency corresponding to this is

f_2=\frac{343}{\frac{1}{3}}=1029\ Hz

for m=2

3.5-3=\frac{5}{2}\cdot \lambda

\lambda =\frac{1}{5}\ m

Frequency corresponding to this wavelength

f_3=\frac{343}{\frac{1}{5}}

f_3=1715\ Hz                        

8 0
3 years ago
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