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belka [17]
3 years ago
12

What do you spiral and elliptical galaxies have in common

Physics
1 answer:
malfutka [58]3 years ago
3 0
They have a uniform luminosity and are similar to the bulge in a spiral galaxy, but with no disk. The stars are old and there is no gas present. Ellipticals are usually found in the high density field, at the centre of clusters.
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A car is traveling at a constant speed of 12m/s , when the driver accelerates the car reaches a speed of 26 m/s in 6s what is th
DaniilM [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed)

Change in speed = (26 m/s) - (12 m/s) = 14 m/s

Time for the change = 6 s

Acceleration = (14 m/s) / (6 s)

Acceleration = (14/6) (m/s²)

<em>Acceleration = 2.33 m/s²</em>

7 0
3 years ago
You need to calibrate your giant paintball bazooka, so you're fired at an angle of 60° and you find that the giant paintball spl
Alexxx [7]

Answer:

Vx = V0 cos 60 = V0 ./ 2        horizontal speed

Vy = V0 sin 69 = V0 * .866 = .866 V0   vertical speed

t = 107 / Vx = 214 / V0   time to travel 107 m

h = Vy t - 1/2 * g t*2   time to fall 1.7 m

-1.7 = .866 V0 * 214 / V0 - 4.9 * (214 / V0)^2           substituting

224400 / V0^2 = 187

V0 = (224400 / 187)^1/2 = 2=34.64 m/s

t = 214 / 34.64 = 6.178 stc

Check:    h = Vy t - 1/2 g t^2

-1.7 = .866 * 34.64 * 6.178 - 4.9 * 6.178^2

-1.7  = -1.69

5 0
3 years ago
For a solar eclipse to occur which of the following alignments must be necessary
katovenus [111]
Very specific alignment of the Sun, Earth, and Moon. If the Moon is lined up precisely with the Sun from the Earth's point of view, the Moon will block Sunlight from reaching the Earth, causing a solar eclipse.
6 0
3 years ago
What is the formula for conservation of momentum
olga55 [171]

Answer:

The general equation for conservation of momentum during a collision between n number of objects is given as: [m i ×v i a ] = [m i ×v i b ] Where m i is the mass of object i , v i a is the velocity of object i before the collision, and v i b is the velocity of object i after the collision.

Explanation:

6 0
3 years ago
Suppose you could fit 100 dimes, end to end, between your card with the pinhole and your dime-sized sunball. how many suns could
Naddika [18.5K]

Answer: 100 suns

Explanation:

We can solve this with the following relation:

\frac{d}{x_{sunball-pinhole}}=\frac{D}{x_{sun-pinhole}}

Where:

d=17.91 mm =17.91(10)^{-3}  m is the diameter of a dime

D is the diameter of the Sun

x_{sun-pinhole}=150,000,000 km=1.5(10)^{11}  m is the distance between the Sun and the pinhole

x_{sunball-pinhole}=100 d=1.791 m is the amount of dimes that fit in a distance between the sunball and the pinhole

Finding D:

D=\frac{d}{x_{sunball-pinhole}}x_{sun-pinhole}

D=\frac{17.91(10)^{-3}  m}{1.791 m} 1.5(10)^{11}  m

D=1.5(10)^{9}  m This is roughly the diameter of the Sun

Now, the distance between the Earth and the Sun is one astronomical unit (1 AU), which is equal to:

1 AU=149,597,870,700 m

So, we have to divide this distance between D in order to find how many suns could it fit in this distance:

\frac{149,597,870,700 m}{1.5(10)^{9}  m}=99.73 suns \approx 100 suns

8 0
3 years ago
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