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Romashka-Z-Leto [24]
3 years ago
8

The subshell letter:a) specifies the 3-D shape of the orbital.b) specifies the principal shell of the orbital.c) specifies the p

rincipal quantum number of the orbital.d) specifies the maximum number of electrons.e) none of the above
Chemistry
1 answer:
Dafna11 [192]3 years ago
3 0

Answer:

a) specifies the 3-D shape of the orbital

Explanation:

To determine the region where is more probable to find the electron, it is characterized by four quantum numbers:

- Principal quantum number (n): represents the level, or shell, where the electron is. It varies from 1 to 7, and are represented by the letters K, L, M, N, O, P, and Q.

-Azimuthal quantum number (l): represents the sublevel, or subshell. Is represented by the letters s, p, d, f, g, ... And by the numbers 0, 1, 2, 3, ... Each one has a 3-D shape, the s, for example, has a spherical shape.

-Magnetic quantum number (ml): represents the orbital inside the subshell, and varies from -l to +l, passing by the 0. Each orbital can have at least 2 electrons.

-Spin quantum number (ms): represents the spin of the electron, which can be +1/2 or -1/2.

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The solubility of copper chloride at 20 °C is 73 g/100 g of water. Kiera adds 100 g of copper chloride to 100 g of water and sti
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Answer:

m_{undissolved}=27g

Explanation:

Hello there!

In this case, according to the given information of the solubility of copper chloride, as the maximum amount of this salt one can dissolve without having a precipitate, we infer that since just 73 grams are actually dissolved, the following amount will remain solid as a precipitate:

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3 0
3 years ago
3. Given the following equation:
miskamm [114]

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

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Number of moles is 2.5 grams = \frac{2.5}{39.098} = 0.064

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

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4 0
3 years ago
216 grams of carbon 36 grams of hydrogen and 288 grams of oxygen whats the empirical formula
schepotkina [342]
Divide each wight by the  relative atomic mass

C = 216 / 12 =  18
H = 36 / 1 = 36
O = 288/16 = 18

Ratio of C:h:O = 1:2:1

Empirical formula is CH2O   Could be formaldehyde HCHO.
4 0
3 years ago
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