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Bezzdna [24]
3 years ago
13

In 8.4 s a fisherman winds 2.9 m of fishing line onto a reel whose radius is 3.0 cm (assumed to be constant as an approximation)

. The line is being reeled in at a constant speed. Determine the angular speed of the reel.
Physics
1 answer:
alukav5142 [94]3 years ago
3 0

Answer:

The angular speed of the reel is 11.33 rad/s

Explanation:

Given

The fisherman takes t = 8.4 s to wind distance x = 2.9 m into a circle radius of r = 3 cm = 0.03 m

Than the tangencial speed equals the change in the distance to the time

v = \frac{x}{t} = \frac{2.9 m}{8.4 s} = 0.34 \frac{m}{s}

Knowing the tangencial velocity is proportional to the radius r and the angular velocity

v = r*w

w = \frac{0.34 m/s}{0.03 m} = 11.33 \frac{rad}{s}

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A sprinter is running the 100 meter dash at a speed of 24 m/s. How long does it the sprinter to finish?
DerKrebs [107]

Answer:

4.1666666 seconds

Explanation:

100 divided by 24 will give you about 4.1666666 seconds or 4 1/6 seconds. Hope it helps!

6 0
3 years ago
To pull a 53 kg crate across a horizontal frictionless floor, a worker applies a force of 180 N, directed 35° above the horizont
Lorico [155]

Answer

given,

mass of the crate  = 53 Kg

force applied by the worker = 180 N

Angle made with the horizontal = 35°

crate moves = 2.9 m

a) The work done equals the force in the direction of the displacement, times the displacement

W = F_x ×d

W = 180 cos 35° × 2.9

W = 427.6 J

b) A force that is perpendicular to the direction of the displacement does not do any work so work done by gravitational force is zero

c) Similarly for the normal force the work done will be zero.

d) Total work done by the crate is equal to 427.6 J

3 0
3 years ago
A 16000 kg railroad car travels along on a level frictionless track with a constant speed of 23.0 m/s. A 5400 kg additional load
Alisiya [41]

Answer:

The speed of the car when load is dropped in it is 17.19 m/s.

Explanation:

It is given that,

Mass of the railroad car, m₁ = 16000 kg

Speed of the railroad car, v₁ = 23 m/s

Mass of additional load, m₂ = 5400 kg

The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :

m_1v_1=(m_1+m_2)v

v=\dfrac{m_1v_1}{m_1+m_2}

v=\dfrac{16000\ kg\times 23\ m/s}{(16000+5400)\ kg}

v = 17.19 m/s

So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.

6 0
2 years ago
Arrange the following in order of their appearance in the life cycle of a star: white dwarf, red giant, main-sequence star. Expl
Goryan [66]
Main-sequence star, red giant, and white dwarf
6 0
3 years ago
Iron has a known density of 7.9g/ml. If a sample of Iron has a mass of 84.5 grams, how many millimeters of water will the sample
dexar [7]

Answer:

10.6962 ml

Explanation:

the density of water is 1g/ml

if you devide the mass by density you get the volume the volume times density is equal to the mass so

84.5 grams devided by 7.9 is equal to 10.6962 ml.

if you do that times 1g/ml is equal to 10.6962 g/ml.

5 0
3 years ago
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