Question

It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°

Answer 1

The answer is 15g, you would use the specific heat formaula

Answer 2

Answer:

$m=14.6g$

Explanation:

You can use the equation $Q=cm(T_{2}-T_{1})$ where Q is the heat, c is the specific heat of the substance, $T_{2}$ and $T_{1}$ are temperature and m is the mass of the substance.

Solving for m we have:

$m=\frac{Q}{c(T_{2}-T_{1})}$

The problem gives you the information about the variables:

$Q=350J$

$c=1.2\frac{J}{g^{o}C}$

$T_{1}=10.0^{o}C$

$T_{2}=30.0^{o}C$

Replacing that values:

$m=\frac{350J}{1.2\frac{J}{g^{o}C}(30.0^{o}C-10.0^{o}C)}$

$m=\frac{350J}{1.2\frac{J}{g^{o}C}(20.0^{o}C)}$

$m=14.6g$