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Yuki888 [10]
3 years ago
9

It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°

Physics
2 answers:
Hitman42 [59]3 years ago
5 0
The answer is 15g, you would use the specific heat formaula
malfutka [58]3 years ago
3 0

Answer:

m=14.6g

Explanation:

You can use the equation Q=cm(T_{2}-T_{1}) where Q is the heat, c is the specific heat of the substance, T_{2} and T_{1} are temperature and m is the mass of the substance.

Solving for m we have:

m=\frac{Q}{c(T_{2}-T_{1})}

The problem gives you the information about the variables:

Q=350J

c=1.2\frac{J}{g^{o}C}

T_{1}=10.0^{o}C

T_{2}=30.0^{o}C

Replacing that values:

m=\frac{350J}{1.2\frac{J}{g^{o}C}(30.0^{o}C-10.0^{o}C)}

m=\frac{350J}{1.2\frac{J}{g^{o}C}(20.0^{o}C)}

m=14.6g

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Divide by ∆t on both sides:  

                ∆X/∆t =  4∆t + 16.8

 Taking the limit as ∆t approaches to zero we get:  

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Answer:

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And when amplitude is halved then power will be 0.0505 watt

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So mass density \mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m

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So if amplitude is halved then power will be \frac{1}{4} times

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