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KonstantinChe [14]
2 years ago
8

A boy weighing 445 N swings on a 2-m long swing. If his horizontal speed at the lowest point is 3 m/s, what total force must the

ropes holding the swing be able to withstand?
Physics
1 answer:
levacccp [35]2 years ago
8 0

Explanation:

We need to calculate the centripetal force:

Fc = W + F

With Fc being the centripetal force, W the weight of the boy, F the centrifugal force (apparent).

We know that we can calculate the apparent centrifugal force thank to the formula:

F = (m·v²)/r = 204N

So we can write:

Fc = W + F = 445N + 204N = 649N

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1. While John is traveling along an interstate highway, he notices a 160-mile marker as he passes through town. Later John passe
pogonyaev

Number of miles that marker shows when passes through town= 160 miles.

Number of miles that marker shows currently to John = 115 miles.

We need to find the distance between town and John's current location.

For the problem, we can clearly see that Town is at 160 miles away but when John passes the marker shows 115 miles.

So, it's just the difference between 160 miles and 115 miles.

In order to find that difference, we need to subtract those two numbers.

160miles - 115miles = 45 miles.

So, we could say the distance between town and John's current location is 45 miles.

4 0
3 years ago
Ls -2 a solution of 4x +3= -5?.<br>​
torisob [31]

Answer:

yes

Explanation:

Let's solve your equation step-by-step.

4x+3=−5

Step 1: Subtract 3 from both sides.

4x+3−3=−5−3

4x=−8

Step 2: Divide both sides by 4.

4x  / 4  =  −8  / 4

x=−2

Hope it helps,

Please mark me as the brainliest

Thank you

5 0
3 years ago
If the bar magnet is flipped over and the south pole is brought near the hanging ball, the ball will be?
disa [49]

The ball may attracted to the magnet.

<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
  • From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
  • As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
  • Steel is a magnetic material.
  • Magnetic materials gets attracted  to the magnet at both the North and South pole.
  • This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.

So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.

Learn more about the bar magnet:

brainly.com/question/27943723

#SPJ4

7 0
1 year ago
At what distance along the central perpendicular axis of a uniformly charged plastic disk of radius 0.390 m is the magnitude of
aliina [53]
<span>Radius, the distance from the centre = 0.390
 Electric field is equal to half of the magnitude. E2 = E / 2
 Given
E1 = E2 E1 = k x Q / r^2
  E2 = (k x Q / r2^2) / 2
  Equating the both we get 2 x r^2 = r2^2
 r2 = square root of (2 x r1^2) = square root of (2) x r = 1.414 x 0.390
  r2 = 1.414 x 0.390 = 0.551 m</span>
3 0
3 years ago
Please help me as soon as possible.
Vilka [71]

Answer:

true

Explanation:

5 0
3 years ago
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