Answer:
4.88 M
Explanation:
M = number moles/Volume (L)
MM AlCl3 = 133.34 g/mol
Volume = 500 mL = 0.5 L
number moles = mass/MM = 325.4/133.34 = 2.44 moles AlCl3
M = 2.44/0.5 = 4.88 M
Answer:
-24.76 kJ/g; -601.8 kJ/mol
Explanation:
There are two heat flows in this experiment.
Heat from reaction + heat absorbed by calorimeter = 0
q1 + q2 = 0
mΔH + CΔT = 0
Data:
m = 0.1375 g
C = 3024 J/°C
ΔT = 1.126 °C
Calculations:
0.1375ΔH + 3024 × 1.126 = 0
0.1375ΔH + 3405 = 0
0.1375ΔH = -3405
ΔH = -24 760 J/g = -24.76 kJ/g
ΔH = -24.76 kJ/g ×24.30 g/mol = -601.8 kJ/mol