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3 years ago

For which purpose do biochemists insert human genes into bacteria?

2 answers:

7 0

Insertion of human genes into bacteria, also known as recombinant DNA technology, is used for the large scale production of human insulin, using bacteria as the insulin-producing machinery. The gene containing information for insulin production is inserted into the DNA of bacteria, which transcribe and translate it, and insulin is produced.

shepuryov [24]3 years ago

7 0

the correct answer is to produce insulin for diabetics

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A rock falls off a cliff and hits the ground after three seconds. What is its velocity right before it hits the ground?

Amiraneli [1.4K]

To solve this kinematics formula use the following equation:

Vf = Vi + at
Vf = 0 + (9.81 m/s^2)(3 seconds)
Vf = 29.43 m/s and or about 29.4 m/s of reported to 3 significant figures.

4 0

4 years ago

Read 2 more answers

True or false ( because water has a high _____ objects will float on it )

eimsori [14]

Objects float on water because it has surface tension.

3 0

4 years ago

Read 2 more answers

State the law of conservation of energy.

LUCKY_DIMON [66]

Answer:

A) The law of conservation of energy states that energy can neither be created nor destroyed.

and

B) Energy can be transferred from one object to another, and it can assume different forms.

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3 years ago

Convert 78.9 kJ into calories Can you also explain how pls? ty

Naddik [55]

Explanation:

1 kJ = 238.85 cal and

1 cal = 0.004187 kJ

so it will be 78.9×238.85 = 18,844 calories

78.9 Kilojoules (kJ) = 18,844 Calories (IT) (cal)

3 0

3 years ago

N2H4 + N2O4 --> N2 + H2O

ahrayia [7]

Answer:

The limiting reagent is N2O4
14,09g

Explanation:

First, we adjust the reaction.

$2N_{2} H_{4}$ + $N_{2} O_{4}$ ⇄ $6N_{2} + 4H_{2}O$

Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.

Using $N_{2} H_{4}$ to form $H_{2}O$

$molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol} H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4} }{32,04\frac{g}{mol} N_{2} H_{4} }$

$molH_{2} O = 1, 125 mol$

Using $N_{2} O_{4}$ to form $H_{2} O$

$molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol} H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4} }{92\frac{g}{mol} N_{2} O_{4} }$

$molH_{2} O = 0,783 mol$

The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.

This is the minimum measure can be formed of each product.

∴ $MassOfH_{2}O = 0,783mol . 18\frac{g}{mol}$

$MassOfH_{2}O = 14,09g$

5 0

4 years ago