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aalyn [17]
3 years ago
7

Is. Fe(s) ---------------> Fe2+(aq) + 2e−oxidation or reduction?​

Chemistry
1 answer:
frez [133]3 years ago
4 0

Answer:

Oxidation occurs at the anode: Fe(s) | Fe2+(aq) half cell. (ii) Reduction occurs at the cathode: Ag(s) | Ag+(aq) half cell. Oxidation occurs at the anode: Pt | Sn2+(aq), Sn4+(aq) half cell. (iii) Electrons flow from the anode to the cathode: from the Pt(s) → Ag(s) electrode.

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