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bonufazy [111]
3 years ago
15

(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylind

er. what is the magnitude of the normal force between the piston and cylinder? (b) what is the magnitude of the force would she have to exert if the steel parts were oiled?
Physics
1 answer:
Vilka [71]3 years ago
8 0
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
F_f = \mu N
where \mu is the coefficient of friction, while N is the normal force. So we have:
F=\mu N
since we know that F=300 N and \mu=0.3, we can find N, the magnitude of the normal force:
N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is \mu=0.03 due to the presence of the oil. Therefore, we have:
N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N
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5. You are pulling a rubber sneaker along concrete
Ainat [17]

Answer:

Fs = 17.66 N

Explanation:

The force of static friction is given by the following formula:

F_s = \mu R = \mu W\\

where,

Fs = The force of static friction = ?

μ = coefficient of static friction = 0.9

W = weight of sneakers = mg

m = mass of sneakers = 2 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

F_s = \mu mg\\F_s = (0.9)(2\ kg)(9.81\ m/s^2)\\

<u>Fs = 17.66 N</u>

3 0
3 years ago
a 1.2 m wire carries a current of 10.0 A in a uniform magnetic field of 0.050T. Find the magnitude of the magnetic force on the
rodikova [14]
To calculate we use the formula for a magnetic force in a current-carrying wire expressed as the product of the current, magnetic field and the length of the wire.
 F = I x L x B

where F is the force on the wire, I is the current flowing on the wire, L is the length of the wire and B is the magnetic field.

F = 10.0 A x 1.2 m x 0.050 T
F = 0.60 N
8 0
3 years ago
According to the nebular theory of solar system formation, what key difference in their early formation explains why the jovian
svp [43]

Answer:

The Jovian planets formed beyond the Frostline while the terrestrial planets formed in the Frostline in the solar nebular

Explanation:

The Jovian planets are the large planets namely Saturn, Jupiter, Uranus, and Neptune. The terrestrial planets include the Earth, Mercury, Mars, and Venus. According to the nebular theory of solar system formation, the terrestrial planets were formed from silicates and metals. They also had high boiling points which made it possible for them to be located very close to the sun.

The Jovian planets formed beyond the Frostline. This is an area that can support the planets that were made up of icy elements. The large size of the Jovian planets is as a result of the fact that the icy elements were more in number than the metal components of the terrestrial planets.

3 0
3 years ago
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mote1985 [20]

Answer:

 1 kg⋅m⋅s−2

Explanation:

I cant really explain it, but thata the answer

3 0
3 years ago
By how much does the gravitational potential energy of a 54-kg pole vaulter change if her center of mass rises about 4.0 m durin
kodGreya [7K]
<span>the gravational potential energy of anything on the ground is zero. When calculating potential energy you take height in meters and multiply it by the mass of the object in kilograms and the acceleration of gravity to get a new unit called Joules. Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.</span>
8 0
3 years ago
Read 2 more answers
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