Answer:
<em>The gravitational potential energy of the parachutist is 3,528,000 J</em>
Explanation:
<u>Gravitational Potential Energy
</u>
It's the energy stored in an object because of its height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where:
m = mass of the object
h = height with respect to a fixed reference
g = acceleration of gravity, usually taken as 
.
The parachutist has a mass of m=120 kg and he jumps at a height of h= 3,000 m. Computing the gravitational potential energy:
U = 120 * 3,000 * 9.8
U = 3,528,000 J
The gravitational potential energy of the parachutist is 3,528,000 J
when an object is revolving in circular path then its velocity is always along the tangent of the circular path
so while moving in circular path if the string is break then due to law of inertia the object will always move in the direction of initial motion
As we know that as per law of inertia if an object will not change its state of motion or state of rest until some external force will act on it.
So here also the object will move along its tangential direction once the string will break
so here the correct path will be
Option B
Answer:
Volume of wood is 68-50 = 18 cm³
Explanation:
<h2>Hope it helps you</h2>
Answer:
D. is always perpendicular to the surface of the conductor
Explanation:
1) Answer is (D) option. Electric field just outside surface of charged conductor is normal to conductor at that point.
It can be explained on the basis of the fact that, Electric field inside conductor under static condition is zero. As a result potential difference between any two points with in conductor is zero. So whole of conductor is equipotential body.
Equipotential surface and Electric field lines always cut at 90 degrees to each other. Conductor being equipotential body, Electric field lines starting or terminating at conductor must be normal to surface. Hence electric field just outside conductor is perpendicular or normal to surface.
