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3 years ago

Given equal time periods, which statement is correct?

Physics

2 answers:

Liono4ka [1.6K]3 years ago

4 0

Answer:

B. Nuclear fusion generates less radioactive waste than nuclear fission.

Explanation:

There are basically two types of nuclear reaction nuclear fusion and nuclear fission. In nuclear fission one molecule breaks into two atoms and generate enormous energy and in nuclear fusion two atoms combined and form a molecule. In nuclear fusion energy released is more than nuclear fission. And waste is generated more in case of nuclear fission.

Mekhanik [1.2K]3 years ago

3 0

The correct option is B.
Nuclear fission and fusion are two different types of nuclear reactions, through which energy may be obtained. Nuclear fission involves the splitting of a molecule into two different part in order to generate energy while nuclear fusion reaction involves the joining together of two elements in other to form one product. Nuclear fission generate much radioactive waste than nuclear fusion. The radioactive waste that is obtainable during nuclear fusion is less than 1% of that produce by nuclear fission.

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In a parallel circuit the current A stays in one path B splits and goes through two components C makes one circle

ArbitrLikvidat [17]

Answer:

B splits and goes through two components

Explanation:

- A series circuit is a circuit in which the components are all connected along the same branch: as a result, the current flowing through the components is the same, while the sum of the potential differences across each component is equal to the emf of the battery

- A parallel circuit is a circuit consisting of separate branches, so that each branch has a potential difference equal to the emf of the battery. As a result, in such a circuit the current in the circuit splits and goes through the different branches/components.

So, the correct answer is

B splits and goes through two components

8 0

3 years ago

A conducting coil of 1850 turns is connected to agalvanometer, and the total resistance of the circuit is 45.0 ohm.The area of e

Xelga [282]

Answer:

0.459 Tesla

Explanation:

Faraday's law:

$Emf = -N\frac{\delta\phi}{\delta t}$

Φ= NAB

V = N Δ (BA) /Δt

the change in BA

was: BA = 0 because initially B was zero.

V=IR

IR = N B A /Δt

q / Δt ×R = N B A / Δt

Or: B = q R / NA = 8.87 x 10^-3 × 45.0 / 1850×4.7 x 10^-4 =

= 0.459 Tesla

3 0

4 years ago

1. If an object that stands 3 centimeters high is placed 12 centimeters in front of a plane

igor_vitrenko [27]

Answer:

1. 12 cm

2. 0.133 m

3. 0.03 m

4. Plane mirror

Virtual image

Upright

Behind the mirror

The same size as the object

Concave mirror when the object is located a distance greater than the focal length from the mirror's surface

Real image

Inverted image

In front of the the mirror

Diminished when the object is beyond the center of curvature

Same size as object when the object is placed at the center of curvature

Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror

Concave mirror when the object is located a distance less than the focal length from the mirror's surface

Virtual image

Upright image

Behind the the mirror

Enlarged

Convex mirror

Type = Virtual image

Appearance = Upright image

Placement = Behind the mirror

Size = Smaller than the object

Explanation:

1. For plane mirror, since there is no magnification, the virtual image distance from the mirror = object distance from the mirror = 12 cm behind the mirror

2. The height of the object = 0.3 m

The distance of the object from the mirror = 0.4 meters

Height of image formed = 0.1 meter

We have;

$Magnification, \ m = \dfrac{Image \ height }{Object \ height } = \dfrac{Image \ distance \ from \ mirror }{Object\ distance \ from \ mirror }$

$m = \dfrac{0.1}{0.3 } = \dfrac{Image \ distance \ from \ mirror }{0.4 }$

Image distance from the mirror = 0.1/0.3×0.4 = 2/15 = 0.133 m

Image distance from the mirror = 0.133 m

3. $m = \dfrac{Image \ height}{0.10 } = \dfrac{0.06 }{0.20 }$

The image height = 0.06/0.2×0.1 = 3/100 = 0.03 meter

The image height = 0.03 meter

4. Plane mirror

Type = Virtual image

Appearance = Upright image with the left transformed to right

Placement = Behind the mirror

Size = The same size as the object

Concave mirror when the object is located a distance greater than the focal length from the mirror's surface

Type = Real image

Appearance = Inverted image

Placement = In front of the the mirror

Size = Diminished when the object is beyond the center of curvature

Same size as object when the object is placed at the center of curvature

Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror

Concave mirror when the object is located a distance less than the focal length from the mirror's surface

Type = Virtual image

Appearance = Upright image

Placement = Behind the the mirror

Size = Enlarged

Convex mirror

Type = Virtual image

Appearance = Upright image

Placement = Behind the mirror

Size = Smaller than the object.

3 0

4 years ago

Above questions which on paper

Luden [163]

Answer:

Explanation:

hghgghfgfgc

6 0

3 years ago

A lead bullet with 30-g of mass traveling at 600 m/s hits a thin iron wall and emerges at a speed of 300 m/s. Suppose 50% of the

TiliK225 [7]

Answer:

liquid state of lead T = 547ºC

Explanation:

The temperature change of the lead bullet can be found by the calorimetry equation

Q = m $c_{v}$ ΔT

Where heat is the energy transferred to lead during the crash, we can find average work

W = F x

With the crash it is very short we can use the average speed of the projectile during the crash

$v_{m}$ = ( $v_{f}$ + v₀) / 2 = (600 + 300) / 2

$v_{m}$ = 450 m / s

This speed of the projectile inside the wall is very inaccurate, but it is better than using any of the two speeds given (initial and final)

W = Δp vm

W = (m $v_{f}$ -m v₀) vm

W = m ( $v_{f}$ -v₀) vm

W = 30 10⁻³ (300-600) 450

W = 4050 J

As we have a shock let's use the momentum

I = F t = ΔP

F = Δp / t

Let's replace

W = (Dp / t) x

With the crash it is very short we can use the average speed of the projectile during the crash

$v_{m}$ = ( $v_{f}$ + v₀) / 2 = (600 + 300) / 2

$v_{m}$ = 450 m / s

This speed of the projectile inside the wall is very inaccurate, but it is better than using any of the two speeds given (initial and final)

W = Δp vm

W = (m $v_{f}$ -m v₀) vm

W = m ( $v_{f}$ -v₀) vm

W = 30 10⁻³ (300-600) 450

W = 4050 J

They tell us that 50% of the heat is absorbed by lead

Q = 50% W

Q = 2025 J

Let's calculate the temperature , the specific heat of lead is

cv = 128 J/kg ºC

Q = m $c_{v}$ Δt

ΔT = Q / m $c_{v}$

ΔT = 2025 / 3010⁻³ 128

$T_{f}$ = 547C

If we review the periodic table, the melting point of lead is 327.3ºC and the boiling point is 1726ºC, since it has a higher temperature than the lead must be in a liquid state

6 0

4 years ago