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ICE Princess25 [194]
3 years ago
11

Suppose you want a telescope that would allow you to see distinguishing features as small as 3.5 km on the Moon some 384,000 km

away. Assume an average wavelength of 550 nm for the light received.Required:What is the minimum diameter mirror on a telescope?
Physics
1 answer:
spayn [35]3 years ago
7 0

Explanation:

\theta=1.22 \frac{\lambda}{D}

And, from equation ( 2 ), we get

\theta=\frac{x}{d}

Thus,

\frac{x}{d} &=1.22 \frac{\lambda}{D}

D &=1.22 \frac{\lambda d}{x}

=1.22 \frac{550 \times 10^{-9} 3.84 \times 10^{8}}{5 \times 10^{3}}

=0.0515 \mathrm{m}

Thus, the diameter of the telescope's mirror that would allow us to see details as small as is

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Use appropriate units and significant figures.  USE THE LAW OF COSINES AND LAW OF SINES.
N76 [4]

Answer:

The resultant velocity is 86.1 mi/h.    

Explanation:

The law of cosines is given by:

c^{2} = a^{2} + b^{2} - 2abcos(\theta)

Where:

c: is the resultant velocity =?

a: is the velocity of the plane = 75.0 mi/h

b: is the velocity of the wind = 15.0 mi/h  

θ: is the angle between "a" and "b"                          

The angle between "a" and "b" can be found as follows:

\theta = 180.0 - 46.0 = 134.0 ^{\circ}

Now, by using the law of cosines we have:

c^{2} = (75.0)^{2} + (15.0)^{2} - 2*75.0*15.0*cos(134.0) = 7413.0

c = 86.1 mi/h    

Therefore, the resultant velocity is 86.1 mi/h.    

The law of sines is:

\frac{a}{sin(\gamma)} = \frac{b}{sin(\alpha)} = \frac{c}{sin(\theta)}

Where:

γ: is the angle between "b" and "c"

α: is the angle between "a" and "c"

So, if we want to find "c" by using the law of sines, we need to know another angle besides θ (γ or α), and the statement does not give us.

I hope it helps you!        

3 0
2 years ago
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.5
Marat540 [252]

Answer:

Option C

Explanation:

From the question we are told that:

Mass m=0.015kg

Radius r=0.5m

Time t=0.70

Generally the equation for Tension is mathematically given by

 T=\frac{4mr}{t^2} \pi

 T=\frac{4*0.015*0.5}{(0.70)^2} (3.142)

 T=0.60N

Therefore

T=0.60 N, toward the center of the circle

Option C

3 0
3 years ago
Which is an example of an abiotic factor in a pond environment?
vesna_86 [32]
"Non-Living" things are known as "Abiotic factor" in the ecosystem.

In short, Your Answer would be: Option A) The Water

Hope this helps!
3 0
3 years ago
Read 2 more answers
An object is moving in a straight line. At t = 0, its speed is 5.0 m/s. From t = 0 to t = 5.0 s, its acceleration is 2.5 m/s2. F
bagirrra123 [75]

Answer:

v1 = a t + v0 = 2.5 * 5 + 5 = 17.5 m/s after 5 sec

v2 = o * 6 + 17.5 = 17.5 m/s after 11 sec

S1 = V0 t + 1/2 a t^2 = 5 * 5 + 1.25 * 5^2 = 56.25 m

S2 = 17.5 * 6 = 105 m

S = 56.3 + 105 = 161 m

Vav = S / t = 161 m / 11 s = 14.6 m/s

3 0
3 years ago
A cylindrical conductor of length l and uniform area of cross section A has a resistance R. Another conductor of length 2l and r
ella [17]

Answer:

2A

Explanation:

The resistance of a wire can be defined as

R = ρL/A

Where,

ρ is Resistivity  - the factor in the resistance which takes into account the nature of the material is the resistivity

L is Length of the conductor

A is Area of cross section of the conductor.

R₁/R₂ = (L₁/L₂) × (A₂/A₁)  ----> rearranging it for A

A₂ = (R₁/R₂) × (L₂/L₁) × A₁  

A₂ = (R/R) × (2L/L) × A  

A₂ = 2A

Therefore, cross section area of another conductor must be 2A

6 0
3 years ago
Read 2 more answers
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