Answer:
f(3) = 362.32 Hz
Explanation:
the formula of frequency of open pipe is
f(n) = (n+1)v/2L
n = 0,1,2,3,... (the order)
0 for the first
1 for the second
v = speed of sound
L = the lenght of pipe
f(3) = (2+1) * 343 / 2 * 1,42
f(3) = 3 * 343 / 2.84
f(3) = 362.324 Hz (or you can write 362.32 Hz
Answer: Fg < Fq
Explanation: just took the lab test edge 2020
Answer:
Energy of scattered photon is 232.27 keV.
Kinetic energy of recoil electron is 497.73 keV.
The recoil angle of electron is 13.40°
Explanation:
The energy of scattered photon is given by the relation :
.....(1)
Here E₁ is the energy of incident photon, E₂ is the energy of scattered photon, 
is mass of electron and θ is scattered angle.
Substitute 730 keV for E₁, 511 keV for and 120° for θ in equation (1).
E₂ = 232.27 keV
Kinetic energy of recoil electron is given by the relation :
K.E. = E₁ - E₂ = (730 - 232.27 ) keV = 497.73 keV
The recoil angle of electron is given by :
Substitute the suitable values in above equation.
= 13.40°
Answer:
The particles in transverse waves move perpendicular to the direction of how the wave moves.
Explanation:
Answer:
1 m = 39.37 in = 39.37/12 ft = 3.28 ft
V = 1145 k/hr = 1145k/hr * 6076 ft/k = 6957020 ft / hr
V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec
V = 1933 ft/sec / (3.28 ft / m) = 589 m/s
Check:
88 ft/sec = 60 mph
(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s
1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph
Also, 1318 / 1145 = 6076 / 5280 as it should
