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Yanka [14]
3 years ago
14

4. What is the coefficient of x in the expression x + 3y + 2? A. 0 B. 1 C. 2 D. 3

Physics
2 answers:
grigory [225]3 years ago
8 0

Answer:

B) 1

Explanation:

There is not a coefficient before x, so automatically the answer is 1

lord [1]3 years ago
7 0

Answer :-

Hi there!

\:\mathsf\red{Your\:answer\:is\:B.\:(1)}

<h2>Explantion :- </h2>

We know

Coefficient is the number or value which should be putten in front of the variable given.

Here,

'x' is the variable. Before <u>x</u>, there is no number mentioned. So the number would be 1.

\:\sf\purple{Hope\:this\:helps\:you!\::)}

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Heater is a compound b/c it is made out of atoms and b/c not all water has the same atoms
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3 years ago
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When the current through a circular loop is 5.7 A, the magnetic field at its center is 3.9 ✕ 10−4 T. What is the radius (in m) o
borishaifa [10]

Radius of the circular loop is 0.0091m.

<h3>What is magnetic field?</h3>

Magnetic field is the area around a magnet where the magnetism influence is felt .

<h3>What is the magnetic field at the centre of a circular loop?</h3>
  • The formula for magnetic field at the centre of a loop is

B =(μ)I/2r

  • where B= Magnetic field at the centre of a circular loop

μ= Magnetic permeability =4(π)*10^(-7)

I= current flowing through the loop

r= radius of the loop

  • Thus, radius of the loop =(4(π)×10^(-7)×5.7)/(2×3.9×10^(-4))

=0.0091m

Thus, we can conclude that the radius of the loop is 0.0091m .

Learn more about magnetic field here :

brainly.com/question/24761394

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8 0
2 years ago
In the aerials competition in skiing, the competitors speed down a ramp that slopes sharply upward at the end. The sharp upward
11111nata11111 [884]

Answer:

u = 11.6 m/s

Explanation:

The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.

Maximum height, H = 10.9

Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :

H=\dfrac{u^2\ sin^2\theta}{g}

10.9=\dfrac{u^2\ sin^2(63)}{9.8}

u = 11.6 m/s

So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.

4 0
3 years ago
A blue car with mass mc = 468 kg is moving east with a speed of vc = 21 m/s and collides with a purple truck with mass mt = 1264
r-ruslan [8.4K]
<span>To calculate the magnitude of the initial momentum of the car in this situation you have to multiple the mass of the blue car times the speed. The mass, 468kg, times the speed, 21 m/s, equals 9828. This means the magnitude of the initial momentum of the blue car in the situation is 9828kg per m/s. In this case, and in simple terminology, the magnitude measures how big something is. So the magnitude of the momentum is just the measurement of how big the initial moment of the car is.</span>
5 0
3 years ago
A car is moving in a straight line with the same speed of 100 m/s ,the acceleration in this
Amiraneli [1.4K]

Answer:

a = 0m/s²

Explanation:

Average acceleration = (change in velocity)/(time it takes). Since the car's change in velocity is zero, its acceleration is zero.

4 0
3 years ago
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