55 Kg has a weight of 55x9.8= 539 N
That is equal to the Normal force.
The static friction = 0.19 x 539 = 102.4 N
Conservation in this case means that it doesn't change. Momentum isn't created or destroyed, but it remains constant.
The mosquito would have a higher pitch but quiet and the croaking bullfrog would be a lower pitch but loud.
Answer:
32.176 ft/s²
9.807 m/s²
Explanation:
Data provided in the question:
Acceleration of the free falling object = 78979.4 mi/hr²
a) In ft/s
Now,
1 mi = 5280 foot
and,
1 hour = 3600 seconds
thus,
78979.4 mi/hr = 
or
78979.4 mi/hr = 32.176 ft/s² ...............(1)
b) In m/s²
Now,
1 foot = 0.3048 m
thus,
we have from 1
32.17 ft/s² = 
or
78979.4 mi/hr = 32.176 ft/s² = 9.807 m/s²