Answer:
This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:
Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.
(a) Frequency of sound wave is inversely proportional to string length.
(b) Pitch of a sound depends on the frequency while loudness depends on the amplitude of sound.
<h3>
Relationship between string length and frequency</h3>
The relationship between string length and frequency is given as;
λ = 2L
where;
- λ is wavelength
- L is length of the string
v = fλ
f = v/λ
f = v/2L
Thus, frequency of sound wave is inversely proportional to string length.
<h3>Relationship between pitch and loudness of sound</h3>
The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.
Learn more about pitch and loudness here: brainly.com/question/61859
Answer:
Explanation:
Sam mass=75kg
Height is 50m
20° frictionless slope
Horizontal force on Sam is 200N
According to the work energy theorem, the net work done on Sam will be equal to his change in kinetic energy.
Therefore
Wg - Ww =∆K.E
Note initial the body was at rest at top of the slope.
Then, ∆K.E is K.E(final) - K.E(initial)
K.E Is given as ½mv²
Since initial velocity is zero then, K.E(initial ) is zero
Therefore, ∆K.E=½mVf²
Wg is work done by gravity and it is given by using P.E formulas
Wg=mgh
Wg=75×9.8×50
Wg=36750J
Ww is work done by wind and it's is given by using formulae for work
Work=force × distance
Ww=horizontal force × horizontal distance
Using Trig.
TanX=opposite/adjacent
Tan20=h/x
x=h/tan20
x=50/tan20
x=137.37m
Then,
Ww=F×x
Ww=200×137.37
We=27474J
Now applying the formula
Wg - Ww =∆K.E
36750 - 27474 =½×75×Vf²
9276=37.5Vf²
Vf²=9275/37.5
Vf²= 247.36
Vf=√247.36
Vf=15.73m/s
Answer:
if the mass of both objects is doubled, then the force of gravity between them is quadrupled and so on
-- Gravity adds 9.8 m/s to the downward speed of any object, every second ... as long as there are no other forces messing with it.
-- In 0.6 sec, gravity added (0.6x9.8)= 5.88 m/s to the downward speed of this ball.
-- This ball didn't start from zero. You threw it down with an initial speed of 1 m/s. So after 0.6 sec, with the help of gravity, its speed is
(1) + (5.88) = 6.88 m/s .
Pick choice-C .
Notice that we don't care how high it was off the ground when you threw it, just as long as it was high enough to keep falling for 0.6 sec without hitting the ground.
