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zloy xaker [14]
3 years ago
6

CN you help me with this question?

Physics
1 answer:
qaws [65]3 years ago
8 0
25% i believe because if were talking 50 percent half it would be 25.


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A paper-filled capacitor is charged to a potential difference of V 0 = 2.5 V V0=2.5 V . The dielectric constant of paper is κ =
forsale [732]

Answer:

V_1=9.25 V

Explanation:

We are given that

V_0=2.5 V

k=3.7

We have to find the new potential difference of the capacitor.

When the capacitor is disconnected then the charge stored in capacitor is constant.

When we introduce material of dielectric constant k between the plates of capacitor then the capacitance of capacitor increases k times.

C_0=\frac{Q}{V_0}

C'=kC=\frac{kQ}{V_1}

\frac{Q}{V_0}=\frac{kQ}{V_1}

V_0=\frac{V_1}{k}

Using the formula

V_0=\frac{V_1}{k}

V_1=V_0k=2.5\times 3.7=9.25 V

Hence, the new potential difference V_1=9.25 V

5 0
3 years ago
The average distance of the planet mercury from the sun is 0.39 times the average distance of the earth from the sun. How long i
Stels [109]

Answer:

T_1=0.24y

Explanation:

Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

(\frac{T_1}{T_2})^2=(\frac{D_1}{D_2})^3

Where T_1 and T_2 are the orbital periods of Mercury and Earth respectively. We have D_1=0.39D_2 and T_2=1y. Replacing this and solving for

T_1^2=T_2^2(\frac{D_1}{D_2})^3\\T_1^2=(1y)^2(\frac{0.39D_2}{D_2})^3\\T_1^2=1y^2(0.39)^3\\T_1^2=0.059319y^2\\T_1=0.24y

5 0
3 years ago
Q11:A police car in hot pursuit goes speeding past you. While the siren is approaching, the frequency of the sound you hear is 5
natulia [17]

Answer:

   v_s = 34.269 m / s

Explanation:

This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.

         f ’= f  \frac{v}{v  \mp v_s  }

where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer

In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together

          5500 = f (\frac{v}{v - v_s })

          4500 = f ( \frac{v}{v + vs})

let's solve these two equations

           \frac{5500}{4500}     = \frac{v+v_s}{v-v_s}

           1.222 (v-v_s) = v + v_s

            v_s (1+ 1.22) = v (1.222 -1)

            v_s = v   \frac{0.222}{2.223}

the speed of sound in air is v = 343 m / s

            v_s = 343 0.09990

 

             v_s = 34.269 m / s

4 0
3 years ago
What is the temperature of a system in thermal equilibrium with another system made up of water and steam at one atmosphere of p
Evgen [1.6K]

Full Question:

What is the temperature of a system in thermal equilibrium with another system made up of water and steam at one atmosphere of pressure?

A) 0°F

B) 273 K

C) 0 K

D) 100°C

E) 273°C

Answer:

The correction Option is D) 100°C

Explanation:

The temperature above is referred to as the critical point.

it is the highest temperature and pressure at which water (which has three phases - liquid, solid, and gas) can exist in vapor/liquid equilibrium. If the temperature goes higher than 100 degrees celsius, it cannot remain is liquid form regardless of what the pressure is at that point.

There is also a condition under which water can exist in its three forms: that is  

- Ice (solid)

- Liquid (fluid)

- Gas (vapor)

That state is called <em>triple point. </em>The conditions necessary for that to occur are:

  • 273.1600 K (0.0100 °C; 32.0180 °F)  as temperature and
  • 611.657 pascals (6.11657 mbar; 0.00603659 atm) as pressure

Cheers

Cheers

8 0
3 years ago
What is the maximum mass of ethyl alcohol you could boil with 2000 j of heat, starting from 19 ∘c?
RSB [31]
The boiling point of ethanol is at 78.37°C. So, the energy must include sensible heat to raise 19°C to the boiling point and latent heat to change liquid to gas. The equation would be

Energy = Sensible heat + Latent heat
Energy = mCpΔT + mΔH

For ethanol, 
Cp = 46.068 + 102,460T - 139.63T² - 0.030341T³ + 0.0020386T⁴ J/kmol·K
ΔH = 38,560 J/mol

Integrate the Cp expression to determine CpΔT:

CpΔT = ∫₂₉₂³⁵²(46.068 + 102,460T - 139.63T² - 0.030341T³ + 0.0020386T⁴ )dT
The upper limit is (78.37+273) = 352 K, while the lower limit is (19 + 273) = 292.
CpΔT = 2384857192 J/kmol·K

2,000 J = m(2384857192 J/kmol)(1 kmol/1000 mol) + m(38,560 J/mol)
m = 8.253×10⁻⁴ moles of ethanol
Since the molar mass of ethanol is 46.07 g/mol,
Mass = (8.253×10⁻⁴ mol)(46.07 g/mol)
Mass = 0.038 g ethanol
8 0
4 years ago
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