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3 years ago

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You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4

n.Ypu carefully add of heat heat energy to he sample and find that its temperature rises.Ehat is the samples specific heat?

1 answer:

lidiya [134]3 years ago

8 0

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy $E=1.25\times10^{4}\ J$

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

$Q=mc\Delta T$

$c=\dfrac{Q}{m\Delta T}$

Where, m = mass

c = specific heat

$\Delta T$ = temperature

Q = heat

Put the value into the formula

$c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}$

$c=14.8\ J/kg. K$

Hence, The samples specific heat is 14.8 J/kg.K

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Read 2 more answers

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Path difference between the waves is given by

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$x_2-x_1=\frac{\lambda }{2}$

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frequency is given by

$f=\frac{v}{\lambda }$

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$f=\frac{343}{1}=343\ Hz$

For next frequency which will cause destructive interference is

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frequency corresponding to this is

$f_2=\frac{343}{\frac{1}{3}}=1029\ Hz$

for $m=2$

$3.5-3=\frac{5}{2}\cdot \lambda$

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