Answer:
570 N
Explanation:
Draw a free body diagram on the rider. There are three forces: tension force 15° below the horizontal, drag force 30° above the horizontal, and weight downwards.
The rider is moving at constant speed, so acceleration is 0.
Sum of the forces in the x direction:
∑F = ma
F cos 30° - T cos 15° = 0
F = T cos 15° / cos 30°
Sum of the forces in the y direction:
∑F = ma
F sin 30° - W - T sin 15° = 0
W = F sin 30° - T sin 15°
Substituting:
W = (T cos 15° / cos 30°) sin 30° - T sin 15°
W = T cos 15° tan 30° - T sin 15°
W = T (cos 15° tan 30° - sin 15°)
Given T = 1900 N:
W = 1900 (cos 15° tan 30° - sin 15°)
W = 570 N
The rider weighs 570 N (which is about the same as 130 lb).
Answer:
Current through each phase Vp = 2.2A
Total three phase power Pt= 1.45kW
Power factor of the load pf = 1
Explanation:
i) Find current through each phase
Vp =220V (rms)
Z =100 Ω
I = Vp/Z
= 220/100
= 2.2A
ii) Find the total three phase power
for a resistive load, Power, P = VI
Power for each phase is given as:
P = 220 * 2.2
= 484 W
Total power TP =3* P
=484*3
= 1452W
=1.45kW
iii) Find the power factor of the load
Phase angle for a resistive load is 0.
α= 0
Hence, power factor of load = cos α
pf = cos 0
pf = 1
Taking notes,because you can read back on what you learned