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SashulF [63]
3 years ago
11

A race car has a maximum speed of 0.104 km/s .What is this speed in miles per hour ?

Physics
1 answer:
sweet [91]3 years ago
8 0

Answer:

232.641374 mph

Explanation:

A race car has a maximum speed of 0.104km/s

Let X represent the speed in miles per hour

Therefore the speed in miles per hour can be calculated as follows

1 km/s = 2,236.936292 mph

0.104km/s = X

X = 0.104 × 2,236.936292

X = 232.641374

Hence the speed in miles per hour is 232.641374 mph

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A submarine can detect an approaching enemy submarine using sonar. If a stationary submerged submarine emits a 100kHz tone and r
kotegsom [21]

Answer:

B) 1.5 m/s

Explanation:

The apparent frequency will be enhanced due to Doppler effect

If f be the apparent frequency , F be the real frequency  , V be the velocity of sound and v be the velocity of approaching submarine then f is given by

f = F \frac{V+v}{V-v}\\

\frac{f}{F} =\frac{V+v}{V-v}\\  

\frac{f}{F}-1  =\frac{V+v}{V-v}-1\\

\Delta f = \frac{2vf}{V-v}\\

200=\frac{2\times v\times 100\times 1000}{1482-v}\\  

v=1.48 m/s

7 0
3 years ago
Find the final velocity of a car that accelerates at +2 m/s2 for +4m from an
Stolb23 [73]

Answer:

Explanation:

according to third equation of motion

2as=vf²-vi²

vf²=2as+vi²

vf=√2as+vi²

vf=√2as+vi

vf=√2*2*4+3

vf=√16+3

vf=4+3=7

so final velocity is 7 m/s

5 0
3 years ago
. When two speakers play different sounds with a constant frequency, beats are heard with a frequency of 5 Hz. If the frequency
morpeh [17]

The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,

F_b = |F_1-F_2|

Our values are given as,

F_b = 5Hz

F_1 = 1050Hz

Using the formula of the frequency I will have,

F_b = |F_1-F_2|

Replacing we have,

5 = |1050-F_2|

F_2 = 1050 \pm 5

F_2 = 1045,1055 Hz

The possible values are two: 1045Hz and 1055Hz

3 0
3 years ago
At 2 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast i
labwork [276]

Answer:

The distance between the ships changing at 6PM is 21.29Km/h

Explanation:

Ship A is sailing east at 35Km/h and ship B is sailing West at 25Km/h

Given

dx/dt= 35

dy/dt= 25

dv/dt= ???? at t= 6PM - 2PM= 4

Therefore t=4

We know ship A travels at 150km in the x-direction and Ship A at t=4 travels at 4.35 Which is 140 also in x-direction

So, we use:

D^2 = (150 - x)^2 + y^2;

D^2 = (150 - 140)^2 + y^2

But ship B travels at t=4, at 4.25 =100 in the y-direction

so, let's use the equation:

D^2 = 10^2 + 100^2

= D= sqrt*(10 + 100)

Lets use 2DD' = 2xx' + 2yy'

Differentiating with respect to t we have:

D•d(D)/dt = -(10)•dx/dt + 100•dy/dt

=100.5 d(D)/dt = (-10)•35 + (100)•25

When t=4, we have x=(140-150) =10 and y=100

= D = sqrt*(10^2 + 100^2)

=100.5

= 100.5 dD/dt = 10.35 +100.25

= dD/dt = 21.29km/h

7 0
3 years ago
A figure skater begins spinning counterclockwise at an angular speed of 3.2 π rad/s. During a 4.5 s interval, she slowly pulls h
avanturin [10]

Answer:

Explanation:

.93 rad per secundo

7 0
2 years ago
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