Given below the arrangement of loading on the larger boat by two tug boats.
F₁ = 5 N
F₂ = 4 N
Angle between them θ = 90⁰
Resultant between two vectors, 
Substituting

So magnitude of the net force on the block = 6.403 N
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Explanation:
Given that,
Mass = 0.254 kg
Spring constant [tex[\omega_{0}= 10.0\ N/m[/tex]
Force = 0.5 N
y = 0.628
We need to calculate the A and d
Using formula of A and d
.....(I)
....(II)
Put the value of
in equation (I) and (II)


From equation (II)


Put the value of
in equation (I) and (II)


From equation (II)


Put the value of
in equation (I) and (II)


From equation (II)


Put the value of
in equation (I) and (II)


From equation (II)


Hence, This is the required solution.
On an incline, the force causing the ball to move downwards would be gravity. Additionally, the component of gravity causing this ball to move downwards would be mgsintheta.
Hope this helps!