Answer:
its a clause
Explanation:
because u have decided to go and go is a action
The proton's electrostatic force exerted on the electron will be 3.5×10¹² N.
<h3>What is the electrostatic force?</h3>
It is a force imposed by one charge on another as a result of the field.
The electrostatic force produced by one line charge on another line charge separated by r is determined by the charge potency of each charge as well as the separation distance between them.
The electrostatic force is found as:
Hence, the proton's electrostatic force exerted on the electron will be 3.5×10¹² N.
To learn more about the electrostatic force refer to the link;
brainly.com/question/9774180
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As waves pass through matter, whether it's a gas, solid, liquid, etc., this matter on a molecular level is displaced (the molecules are displaced) and this translates to kinetic energy.
Answer:
P = 2.45 N
Q = 6.65 N
Explanation:
According to Newton's 2nd Law:
Unbalanced Force = ma
where,
m = mass = 7 kg
a = acceleration
In the first case when both forces P and Q act on left side:
Unbalanced Force = P + Q
a = 1.3 m/s²
Therefore,
P + Q = (7 kg)(1.3 m/s²)
P + Q = 9.1 N ------------------------- equation 1
Now, in second case when both forces have different directions:
Unbalanced Force = Greater Force - Smaller Force
Unbalanced Force = Q - P
a = 0.6 m/s²
Therefore,
Q - P = (7 kg)(0.6 m/s²)
Q - P = 4.2 N ------------------- equation 2
Adding equation 1 and equation 2, we get:
(Q + P) + (Q - P) = 9.1 N + 4.2 N
2 Q = 13.3 N
<u>Q = 6.65 N</u>
Using this value in equation 2, we get:
6.65 N - P = 4.2 N
<u>P = 2.45 N</u>
Answer:
The average force exerted on the man by the ground therefore is 153.319.53 N
Explanation:
Given the following information
Mass of man, m = 75 kg
height of fall, h = 0.48 cm
velocity just before landing, v = 4.43 m/s
We therefore have
The work required to break the fall is equal to the kinetic energy of motion, just before touching the ground
Work done = Energy to absorb Kinetic Energy KE = 0.5·m·v²= F·h
Where:
F = Force required to break the fall
Therefore the force, F = (0.5·m·v² )/h
= 0.5×75 kg ×(4.43 m/s)²/(0.0048 m) = 153319.53 N
The average force exerted on him by the ground is therefore
= 153319.53 N.