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yKpoI14uk [10]
3 years ago
6

Your car's speedometer works in much the same way as its odometer, except that it converts the angular speed of the wheels to a

linear speed of the car, assuming standard-size tires and no slipping on the pavement. Part A If your car has standard 24-in.-diameter tires, how fast are your wheels turning when you are driving at a freeway speed of 35 mph
Physics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

Speed will be 30810 rpm      

Explanation:

We have given diameter of the tire d = 24 inch

So radius r=\frac{d}{2}=\frac{24}{2}=12imch

We have given linear velocity v = 35 mph

We know that linear velocity is given by v=\omega r

35=\omega \times 12

\omega =\frac{35}{12}\times \frac{63360}{60}=3080rad/min

As we know that 1 mile = 63360 inch and 1 hour = 60 min

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Snorkeling by humans and elephants. When a person snorkels, the lungs are connected directly to the atmosphere through the snork
fgiga [73]

Answer:

2354.4 Pa

40221 Pa

Explanation:

\rho = Density = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth

The pressure difference would be

\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 0.24\times 9.81\\\Rightarrow \Delta P=2354.4\ Pa

The pressure difference in the first case is 2354.4 Pa

\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 4.1\times 9.81\\\Rightarrow \Delta P=40221\ Pa

The pressure difference in the second case is 40221 Pa

7 0
3 years ago
A uniform electric field of 2 kNC-1 is in the x-direction. A point charge of 3 μC initially at rest at the origin is released. W
ANEK [815]
The electric force acting on the charge is given by the charge multiplied by the electric field intensity:
F=qE
where in our problem q=3 \mu C= 3 \cdot 10^{-6} C and E=2 kN/C=2000 N/C, so the force is
F=(3 \cdot 10^{-6} C)(2000 N/C)=0.006 N

The initial kinetic energy of the particle is zero (because it is at rest), so its final kinetic energy corresponds to the work done by the electric force for a distance of x=4 m:
K(4 m)=W=Fd=(0.006 N)(4 m)=0.024 J
8 0
3 years ago
How does the sun’s gravitational attraction impact Earth’s motion?
Tasya [4]
The Sun's gravitational pull keeps our planet orbiting the Sun <span>in a nice nearly-circular orbit.</span>
7 0
3 years ago
What are two ways an engineer can build a car in order for it to accelerate faster
Ket [755]

Explanation:

Take F=ma

a = F/m

For a higher, F higher or m lower

Means higher horse power for engine or lower mass for the car

4 0
2 years ago
when astronauts work in space, they are sometimes attached to the spacecraft by a line called an umbilical. Why do you think the
wariber [46]
Probably for the umbilical cord that connects babies (from their early stages in the womb to their removal) to their mothers. The cord is cut, forming the belly button. This is analogous to astronauts in space.
3 0
3 years ago
Read 2 more answers
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