Two plane mirrors make the angle α = 46.0 ° α=46.0° between them. A ray of light incident on one of the mirrors is reflected and
it hits the second mirror. Find the angle between the ray incident on the first mirror and the ray reflected off of the second mirror.
1 answer:
Answer:
β = 88°
Explanation:
Given,
Angle between the mirror, α = 46.0 °
Let 'i' and 'r' be the angle made with mirror by incident and reflected ray respectively.
Now,
α + i + r = 180°
i + r = 180°-46°
i + r = 134°
we know, angle of incidence and angle of reflection are equal.
Let β be the required angle
β + (180°-2i) + (180°-2r) = 180°
β -2(i+r) = -180
β = -180° + 2 x 134°
β = 88°
Hence, the angle between them is equal to 88°.
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Answer:
Time period of horizontal Oscillation = T = 2
As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.
Explanation:
Solution:
As we know that:
F = Kx
Here,
K = Spring constant
x = displacement.
First, they are displacing it with 6 cm from its rest position for which Time period of the oscillation is T = 2 seconds.
But next, they want to know the effect on the time period of the oscillation if the displacement x is doubled from 6cm to 12 cm.
First of all, let us see the equation of the time period of the oscillation.
We need to check, if time period does depend on the displacement or not.
As we know,
Time period of horizontal Oscillation = T = 2
As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.
Since, K is the constant for a particular spring, we need to change the mass of the cart to change the time period.
Hence the Time period will remain same.