Two plane mirrors make the angle α = 46.0 ° α=46.0° between them. A ray of light incident on one of the mirrors is reflected and
it hits the second mirror. Find the angle between the ray incident on the first mirror and the ray reflected off of the second mirror.
1 answer:
Answer:
β = 88°
Explanation:
Given,
Angle between the mirror, α = 46.0 °
Let 'i' and 'r' be the angle made with mirror by incident and reflected ray respectively.
Now,
α + i + r = 180°
i + r = 180°-46°
i + r = 134°
we know, angle of incidence and angle of reflection are equal.
Let β be the required angle
β + (180°-2i) + (180°-2r) = 180°
β -2(i+r) = -180
β = -180° + 2 x 134°
β = 88°
Hence, the angle between them is equal to 88°.
You might be interested in
Answer:
Explanation:
Momentum is the product of mass and velocity.
The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.
Substitute the values into the formula and multiply.
The truck's momentum is <u>70,000 kilograms meters per second.</u>
The equivalent resistance of several devices connected in parallel is given by
where
are the resistances of the various devices. We can see that every time we add a new device in parallel, the term 
increases, therefore the equivalent resistance of the circuit 
decreases.
But Ohm's law:
tells us that if the equivalent resistance decreases, the total current in the circuit increases. The power dissipated through the circuit (and so, the heat produced) depends on the square of the current:
therefore if there are too many devices connected in parallel, this can be a problem because there could be too much power dissipated (and too much heat) through the circuit.
where
But Ohm's law:
tells us that if the equivalent resistance decreases, the total current in the circuit increases. The power dissipated through the circuit (and so, the heat produced) depends on the square of the current:
therefore if there are too many devices connected in parallel, this can be a problem because there could be too much power dissipated (and too much heat) through the circuit.