Ask question

Ask question

All categories

2 years ago

8

Two plane mirrors make the angle α = 46.0 ° α=46.0° between them. A ray of light incident on one of the mirrors is reflected and

it hits the second mirror. Find the angle between the ray incident on the first mirror and the ray reflected off of the second mirror.

1 answer:

user100 [1]2 years ago

6 0

Answer:

β = 88°

Explanation:

Given,

Angle between the mirror, α = 46.0 °

Let 'i' and 'r' be the angle made with mirror by incident and reflected ray respectively.

Now,

α + i + r = 180°

i + r = 180°-46°

i + r = 134°

we know, angle of incidence and angle of reflection are equal.

Let β be the required angle

β + (180°-2i) + (180°-2r) = 180°

β -2(i+r) = -180

β = -180° + 2 x 134°

β = 88°

Hence, the angle between them is equal to 88°.

You might be interested in

In this type of bond, electrons are lost or gained by atoms, and the atoms are held together by electrical attraction.

expeople1 [14]

<span>In Ionic type of bonding, electrons are lost (more protons than electrons and positive charge) or gained (more electrons than protons, still a negative charge) by atoms, and the atoms are held together by electrical attraction in the process. Covalent bondings are the sharing of electrons as well as partial bondings. Covalent bondings’ electrons have the same charges thus, there is no gaining or losing electrons in the process of sharing. Strong bondings are applicable only to Hydrogen (H) atoms. </span>

8 0

2 years ago

Falling raindrops frequently develop electric charges. Does this create noticeable forces between the droplets? Suppose two 1.8

umka2103 [35]

Answer:

a) $F=2.048\times 10^{-7}\ N$

b) $a=0.1138\ m.s^{-2}$

Explanation:

Given:

mass of raindrops, $m=1.8\times 10^{-6}\ kg$

charge on the raindrops, $q=+21\times 10^{-12}\ C$

horizontal distance between the raindrops, $r=0.0044\ m$

A)

<u>From the Coulomb's Law the force between the charges is given as:</u>

$F=\frac{1}{4\pi.\epsilon_0} .\frac{q_1.q_2}{r^2}$

we have:

$\epsilon_0=8.854\times 10^{-12}\ C^2.N^{-1}.m^{-2}$

<em>Now force:</em>

$F=\frac{1}{4\pi\times 8.854\times 10^{-12}} .\frac{21\times 10^{-12}\times 21\times 10^{-12}}{0.0044^2}$

$F=2.048\times 10^{-7}\ N$

B)

<u>Now the acceleration on the raindrops due to the electrostatic force:</u>

$a=\frac{F}{m}$

$a=\frac{2.048\times 10^{-7}}{1.8\times 10^{-6}}$

$a=0.1138\ m.s^{-2}$

7 0

2 years ago

Read 2 more answers

A child stands on the edge of a merry-go-round of radius 1.63 m which is rotating at 2.13 rad/s.

Brilliant_brown [7]

Answer:

9

Explanation:

2.13 rad/s * 26.9 sec

2.13 * 26.9

57.297

3282.88 deg / 360 deg = 9.12

It makes 9 complete revolutoins

7 0

1 year ago

You have covered a grounded metal surface with a layer of photoconductor. Working in the dark, you sprinkle negative charge onto

Keith_Richards [23]

Answer:

A. the left half becomes neutral while the right half remains negatively charged

Explanation:

This is because wherever light strikes the photoconductor, it transforms from an insulator into a conductor. The charge will then migrate through it and leaves its surface. By exposing the left half of the photoconductor to light, you allow its local charge to leave and it becomes neutral.

6 0

2 years ago

A car and a motorcycle start from rest at the same time on a straight track, but the motorcycle is 25.0 m behind the car. The ca

sergeinik [125]

Answer:

t = 8.45 sec

car distance d = 132.09 m

bike distance d = 157.08 m

Explanation:

GIVEN :

motorcycle is 25 m behind the car , therefore distance need to covered by bike to overtake car is 25+ d, when car reache distance d at time t

for car

by equation of motion

$d = ut + \frac{1}{2}at^2$

u = 0 starting from rest

$d = \frac{1}{2}at^2$

$t^2 = \frac{2d}{a}$

for bike

$d+25 = 0 + \frac{1}{2}*4.40t^2$

$t^2= \frac{d+25}{2.20}$

equating time of both

$\frac{2d}{a} = \frac{d+25}{2.20}$

solving for d we get

d = 132 m

therefore t is $= \sqrt{\frac{2d}{a}}$

$t = \sqrt{\frac{2*132}{3.70}}$

t = 8.45 sec

each travelled in time 8.45 sec as

for car

$d = \frac{1}{2}*3.70 *8.45^2$

d = 132.09 m

fro bike

$d = \frac{1}{2}*4.40 *8.45^2$

d = 157.08 m

7 0

2 years ago