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rusak2 [61]
3 years ago
8

Two plane mirrors make the angle α = 46.0 ° α=46.0° between them. A ray of light incident on one of the mirrors is reflected and

it hits the second mirror. Find the angle between the ray incident on the first mirror and the ray reflected off of the second mirror.

Physics
1 answer:
user100 [1]3 years ago
6 0

Answer:

β = 88°

Explanation:

Given,

Angle between the mirror, α = 46.0 °

Let 'i' and 'r' be the angle made with mirror by incident and reflected ray respectively.

Now,

α + i + r = 180°

i + r = 180°-46°

i + r = 134°

we know, angle of incidence and angle of reflection are equal.

Let β be the required angle

β + (180°-2i) + (180°-2r) = 180°

β -2(i+r) = -180

β = -180° + 2 x 134°

β = 88°

Hence, the angle between them is equal to 88°.

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Answer:

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In a very large closed tank, the absolute pressure of the air above the water is 6.46 x 105 Pa. The water leaves the bottom of t
a_sh-v [17]

Answer:

a) 35.94 ms⁻²

b) 65.85 m

Explanation:

Take down the data:

ρ = 1000kg/m3

a) First, we need to establish the total pressure of the water in the tank. Note the that the tanks is closed. It means that the total pressure, Ptot,  at the bottom of the tank is the sum of the pressure of the water plus the air trapped between the tank rook and water. In other words:

Ptot = Pgas + Pwater

However, the air is the one influencing the water to move, so elimininating Pwater the equation becomes:

Ptot  = Pgas

        = 6.46 × 10⁵ Pa

The change in pressure is given by the continuity equation:

ΔP = 1/2ρv²

where v is the velocity of the water as it exits the tank.

Calculating:

6.46 × 10⁵  =1/2 ×1000×v²

solving for v, we get v = 35.94 ms⁻²

b) The Bernoulli's equation will be applicable here.

The water is coming out with the same pressure, therefore, the equation will be:

ΔP = ρgh

6.46 × 10⁵  = 1000 x 9.81 x h

h = 65.85 meters

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3 years ago
If the kinetic energy of a 10 kilogram object is 2000 joules It’s velocity is
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<h2>✨✨✨✨✨✨✨✨✨✨✨</h2><h2><em><u>hope it helps you see the attachment for further information.....</u></em></h2><h2 /><h2><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em></h2>

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3 years ago
Calculate kinetic energy of an 86kg scooter moving at 18 m/s
myrzilka [38]

Calculate the kinetic energy of an 86-kg scooter moving at 18 m/s?

K.E.      =      (1/2)mv^2

K.E.      =        (1/2)86   *   18^2

K.E.       =         (Answer  Unit)     =====>    J

M     =      86kg

V      =        18 m/s

Significant Figures  ======>    6

Answer:   ======>   KE     =      13932 J



Show work:

1/2  *    86   *   18^2

(1/2)86  *  18^2

Remove Parenthesis:      

a        =       a

1/2 *  86  *  18^2

Multiply Fractions:

a * b/c     =    a  *  b/c

=     1  *  86  *  18^2/2

Multiply the numbers:

1  *  86     =     86

18^2    *    86/2

Divide the numbers:

86/2     =     43

18^2   *    43

18^2     =     324

43    *    324

Multiply the numbers:

43   *    324

13932

Therefore,  Your answer   is    KE    =     13932 J



Hope that helps!!!!                                   : )  sorry for the long explanation!!!








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How far does the bullet penetrate and how do I figure this out?
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-- work = (avg force) x (penetration) and they just gave you the average force.

-- Did you think it would be this easy ?

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