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rusak2 [61]
2 years ago
8

Two plane mirrors make the angle α = 46.0 ° α=46.0° between them. A ray of light incident on one of the mirrors is reflected and

it hits the second mirror. Find the angle between the ray incident on the first mirror and the ray reflected off of the second mirror.

Physics
1 answer:
user100 [1]2 years ago
6 0

Answer:

β = 88°

Explanation:

Given,

Angle between the mirror, α = 46.0 °

Let 'i' and 'r' be the angle made with mirror by incident and reflected ray respectively.

Now,

α + i + r = 180°

i + r = 180°-46°

i + r = 134°

we know, angle of incidence and angle of reflection are equal.

Let β be the required angle

β + (180°-2i) + (180°-2r) = 180°

β -2(i+r) = -180

β = -180° + 2 x 134°

β = 88°

Hence, the angle between them is equal to 88°.

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The true mass of the aluminium is given by

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Put all the values in above equation we get

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Put the value into the formula

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Put the value into the formula

v=\sqrt{(16.5)^2+(-0.82)^2}

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(b). The maximum height of the ball is 41.67 m

(c). The ball's impact speed is 16.52 m/s.

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