Two plane mirrors make the angle α = 46.0 ° α=46.0° between them. A ray of light incident on one of the mirrors is reflected and
it hits the second mirror. Find the angle between the ray incident on the first mirror and the ray reflected off of the second mirror.
1 answer:
Answer:
β = 88°
Explanation:
Given,
Angle between the mirror, α = 46.0 °
Let 'i' and 'r' be the angle made with mirror by incident and reflected ray respectively.
Now,
α + i + r = 180°
i + r = 180°-46°
i + r = 134°
we know, angle of incidence and angle of reflection are equal.
Let β be the required angle
β + (180°-2i) + (180°-2r) = 180°
β -2(i+r) = -180
β = -180° + 2 x 134°
β = 88°
Hence, the angle between them is equal to 88°.
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Answer:
3.28 cm
Explanation:
To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:
r =
Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.
The mass and charge of a proton are:
m = 1.67 * 10^-27 kg
q = 1.6 * 10^-19 C
So, we get that the radius r will be:
r = = 0.0328 m, or 3.28 cm.
