3 years ago

Currently, Earth's tilt is closest to _____.

1 answer:

4 0

The answer is C. 23.5°. It's because of this tilt that the Earth experiences seasons as it orbits around the Sun. Imagine the Sun is at the center of a spinning record.

You might be interested in

the temperature of a body fell from 100°c to 50°c in 10 minutes. the surrounding temperature was 20°c. what is the temperature a

Anna007 [38]

Answer:

The temperature is 10 c

4 0

3 years ago

Two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 221

8_murik_8 [283]

Answer:

v = 8.8 m /s

Explanation:

For listener and source going away from each other the formula of Doppler effect is as follows

$\frac{f}{f_0} = \frac{V-v}{V+v}$

V is velocity of sound , v is velocity of listner and source of sound

f₀ is apparent frequency and f is real frequency

V = 343 , v = ? ,f = 210 , f₀ = 221

Put these value in the relation above

$[tex]\frac{210}{221} = \frac{343-v}{343+v}$ [/tex]

v = 8.8 m /s

6 0

3 years ago

Describe and contrast inversion and eversion?

Kitty [74]

Answer:

inversion would be going toward or inside internal and eversion is going outside or external

7 0

3 years ago

If an object placed in a fluid experiences a buoyant force equal to the weight of the fluid it displaces, the object will float.

enyata [817]

Answer: The answer is False

Explanation: This is for the one's in apex <>

6 0

3 years ago

The membrane that surrounds a certain type of living cell has a surface area of 5.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A

kotykmax [81]

Answer:

$2.1\times 10^{-12} c$

Explanation:

We are given that

Surface area of membrane= $5.3\times 10^{-9} m^2$

Thickness of membrane= $1.1\times 10^{-8} m$

Assume that membrane behave like a parallel plate capacitor.

Dielectric constant=5.9

Potential difference between surfaces=85.9 mV

We have to find the charge resides on the outer surface of membrane.

Capacitance between parallel plate capacitor is given by

$C=\frac{k\epsilon_0 A}{d}$

Substitute the values then we get

Capacitance between parallel plate capacitor= $\frac{5.9\times 8.85\times 10^{-12}\times 5.3\times 10^{-9}}{1.1\times 10^{-8}}$

$C=0.25\times 10^{-12}F$

V= $85.9 mV=85.9\times 10^{-3}$

$Q=CV$

$Q=0.25\times 10^{-12}\times 85.9\times 10^{3}=2.1\times 10^{-12} c$

Hence, the charge resides on the outer surface= $2.1\times 10^{-12} c$

5 0

3 years ago

Read 2 more answers