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3 years ago

Describe what a hydrogen bond is. 6th grade answer

Physics

1 answer:

r-ruslan [8.4K]3 years ago

8 0

Answer:

<em>Hydrogen bond is the attractive force between the hydrogen attached electronegative atom </em>

Explanation:

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A bar-magnet with magnetic moment 2.5 Am^2 is placed in a homogeneous magnetic field (of 0.1 T that is directed along the z-axis

Angelina_Jolie [31]

Answer:

Force on bar magnet = 0

Torque on bar magnet = 0

Force on bar magnet = 0

Torque on bar magnet = 0.177 Nm

Force on bar magnet = 0

Torque on bar magnet = 0.25 Nm

Explanation:

Part 1)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

$\tau = MBsin\theta$

when bar magnet is inclined along z axis along magnetic field

then we will have

$\tau = MBsin0 = 0$

Part 2)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

$\tau = MBsin\theta$

when bar magnet is pointing 45 degree with z axis then we will have

$\tau = MBsin45$

$\tau = (2.5)(0.1)sin45$

$\tau = 0.177 Nm$

Part 3)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

$\tau = MBsin\theta$

when bar magnet is pointing 90 degree with z axis then we will have

$\tau = MBsin90$

$\tau = (2.5)(0.1)sin90$

$\tau = 0.25 Nm$

8 0

3 years ago

A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated during the time interval Δt f

anzhelika [568]

Answer:

$\phi_i = BA$

Explanation:

magnetic flux is the count of magnetic field lines passing through a given loop or area

As we know that magnetic flux is given by the formula

$\phi = \vec B. \vec A$

here we also know that magnetic field B and plane of the coil is perpendicular in initial position

So the area vector is always perpendicular to the plane of the coil

so the angle between magnetic field and area vector is parallel to each other and this angle would be zero

so magnetic flux of the coil initially we have

$\phi = BAcos0 = BA$

6 0

3 years ago

An electron and a second particle both move in circles perpendicular to a uniformmagnetic field. The mass of the second particle

Katarina [22]

Answer:

The change on the second particle is $2.93\times 10^{-16}\ C$ .

Explanation:

The period of revolution of the particle in the magnetic field is given by the formula as follows :

$T=\dfrac{2\pi m}{Bq}$

It is given that the magnetic field is uniform. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton.

$m_s=m_p$

If both particles take the same amount of time to go once around their respective circles. So,

$T_e=T_s\\\\\dfrac{2\pi m_e}{Bq_e}=\dfrac{2\pi m_s}{Bq_s}\\\\\dfrac{m_e}{q_e}=\dfrac{m_p}{q_s}\\\\q_s=\dfrac{m_pq_e}{m_e}\\\\q_s=\dfrac{1.67\times 10^{-27}\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}\\\\q_s=2.93\times 10^{-16}\ C$

So, the change on the second particle is $2.93\times 10^{-16}\ C$ .

7 0

3 years ago

What is lever means,types of lever.. <br>will give brainles

serious [3.7K]

Explanation:

A lever is a rigid bar which moves freely about a fixed point called fulcrum....

The types of lever are :

First class lever
Second class lever
Third class lever....

3 0

2 years ago

What effects do coil of wire on a compass after it has been connected to a battery

Yanka [14]

Explanation:

The compass needle moved when the wire was connected to the battery. The important point here is that the needle is affected by the wire only when both ends of the wire are connected to the battery because only at this time is current flowing through the circuit.

8 0

3 years ago