The answer is AlCl3, it’s 133.34g/mol
Take note of the subscript written for each element in the compound. To find the total number of moles, make sure to multiply the subscript with the number of moles of compound. The answer for each is written below:
a. 3*1 = 3 moles Nitrogen; 3*3 = 9 moles Hydrogen
b. 0.25*2 = 0.5 moles Hydrogen; 0.25*1 = 0.25 moles Oxygen
c. 5*2 = 10 moles Hydrogen; 5*1 =5 moles Sulfur; 5*4 = 20 moles Oxygen
d. 0.75*1 = 0.75 moles Calcium; 0.75*1*2 = 1.5 moles Nitrogen; 0.75*3*2 = 4.5 moles Oxygen
Answer:
The attractive forces between them is very weak
Explanation:
Since the mole ratio is 1 to 1 for this reaction, you can just use M1V1 = M2V2 to solve, given that 1 refers to HBr and 2 refers to LiOH.
M1 = ?
V1 = 0.40 L
M2 = 0.50 M
V2 = 0.20 L
M1(0.40) = (0.50)(0.20)
Solve for M1 —> M1 = (0.50)(0.20)/0.40 = 0.25 M HBr
Answer:
Explanation:
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