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ad-work [718]
3 years ago
6

A reaction requires 15.0 g of ammonium chloride. What volumeof a

Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

103 cm³

Explanation:

A reaction requires 15.0 g of ammonium chloride. The percent by mass of ammonium chloride in the solution is 14%. The mass of the solution required is:

15.0 g ammonium chloride × (100 g solution/ 14 g ammonium chloride) = 107 g solution

The density of the solution is 1.04 g/cm³. The volume of solution corresponding to 107 g is:

107 g × (1 cm³/ 1.04 g) = 103 cm³

In 103 cm³ of a 14% solution, there will be 15.0 g of ammonium chloride.

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Name the unit being abbreviated in each measurement (spelling counts). Only write the name of the unit, do not include the numbe
givi [52]

Answer:

Litre (L) , Centimetre (cm) , Kilogram (Kg), Seconds (s) and Kelvin (K)

Explanation:

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Option (3) 334J.

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The following data were obtained from the question:

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3 0
3 years ago
Suppose that 10.1 mL of HNO3 is neutralized
Vedmedyk [2.9K]

Answer:

0.0251 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

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Next, the data obtained from the question. This include the following:

Volume of acid (Va) = 10.1mL

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MaVa/MbVb = nA/nB

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Therefore, the molarity of HNO3 is 0.0251 M

6 0
3 years ago
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