Heat is most closely related to THERMAL energy.
Answer: Their u go i found it their was about 3 pages i did not no what pages u had to do.
Explanation:
Answer:
See below
Explanation:
Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N
no work is done by this force
Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N
work of friction = 7.55 * 2 m = 15.1 j
Force Downplane = mg sin 53 = 62.61 N
work = 62.61 * 2 = 125.22 j
Net Force downplane = force downplane - force friction = 55.06 N
net Work = force * distance = 55.06 N * 2 M = 110.12 j
Answer:
B. to the right
Explanation:
Given:
- distance of the test charge from +Q, r
- distance of test charge from +2Q, 2r
<u>Force on the test charge due to +Q:</u>
<u>Force on the test charge due to +Q:</u>
Since all the charges are positive here, so they will try to repel the test charge away. And the force due to charge +Q will be greater so initially the test charge will move rightwards away from the +Q charge.
D. It is about 100,000 times larger.
A commonly used comparison is that of a pea in the middle of a racetrack.
