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Arisa [49]
3 years ago
5

Explain how the rabbit depend on energy from the sun.

Physics
2 answers:
AveGali [126]3 years ago
6 0
Its surroundings ,the sun and its habitat and ecosystem
Grace [21]3 years ago
5 0
The rabbit depends on the energy of the sun because the plants the rabbit eats need the sun to reproduce and to go through photosynthesis to grow over and over again for the rabbit to have food.
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Which quantity may be calculated directly using Newton's second law of motion?
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Answer:

Weight

Explanation:

The second law of motion by Newton can be used to determine weight.

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They occupy the space surrounding the nucleus of the atom, they have a -1 charge
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Electrons.

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Look it up.

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3 years ago
How much heat energy is tequired to raise the temperature of 3 kg of copper from 0
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2 would be the answer

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4 years ago
A 67 kg kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m m . What is the effective s
amid [387]

Point of correction, spring constant is 2.3×10−2 m not 2.3×10−2 m m

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28577 N/m

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From Hooke's law, F=kx where F is force applied, k is spring constant and x is compression

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k=\frac {mg}{x}

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8 0
3 years ago
Sitting in a second-story apartment, a physicist notices a ball moving straight upward just outside her window. The ball is visi
gregori [183]

Answer:

1.013 s

Explanation:

You  can solve this problem using the equations for constant acceleration motion. The velocity at the bottom of the window can be found using this expression:

(x-x_o) = \frac{1}{2} at^2 + v_ot = -\frac{1}{2}gt^2 + v_ot

the gravity is negative as it opposes the movement.

(x-x_o) = -\frac{1}{2}gt^2 + v_ot\\v_o = \frac{(x-x_o)+\frac{1}{2}gt^2}{t} = \frac{1.19m+\frac{1}{2} 9.81m/s^2(0.2s)^2}{0.2s} = 6.931 m/s

Now, the time elapsed before the ball reappears is 2 times the time that it takes for the ball to go from the bottom of the window, reach maximum height, and reach again the bottom of the window, minus 2 times the time that it takes for the ball to travel from the top to the bottom of the window. The time that takes to the ball to reach maximum height, or in other words, to time that takes for the velocity of the ball to go from vo to 0m/s:

t_1 = \frac{0m/s - v_o}{g}  = \frac{-6.931 m/s}{-9.81m/s^2} = 0.706 s

Then:

t = 2t_1 - 2*0.2s = 2*(0.706s) - 0.4s = 1.013 s

7 0
3 years ago
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