m1= mass 1 = 1.1 kg
Vi1 = initial velocity 1 = 2.7 m/s
m2= 2.4 kg
V2i = -1.9 m/s
We assume east as positive and west as negative.
Apply the formulas:
Vf1 = ?
Replacing:
Answer: 3.6 m/s west
If you launch a projectile at an angle greater than 45 ° it’s horizontal range will not reach as far as if you had launched it a
2 answers:
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Answer:
Explanation:
As we know that the acceleration due to gravity decreases with height.
At certain height it will get to the half of its value on the surface of the earth.
As we know that the weight on the surface of the earth is given as:
where:
m = mass of the object
g = acceleration due to gravity of the substance
Since mass of the substance is constant so the variation is weight is possible only due to change in the acceleration due to gravity.
<u>We know that the variation of the acceleration due gravity with height is given as:</u>
where:
value to acceleration due to gravity at height h
g = acceleration due to gravity at the earth's surface
h = height of the object
R = radius of the earth =
according to question the weight becomes half, so,:
is the height a rocket has to go above Earth's surface before its weight is half of what it is on Earth.
Answer:
a
b
c
Explanation:
From the question we are told that
The magnitude of electric dipole moment is
The electric field is
The distance between the positive and negative charge center is mathematically evaluated as
Where e is the charge on one electron which has a constant value of
Substituting values
The maximum torque is mathematically represented as
Here
This because at maximum the molecule is perpendicular to the field
substituting values
The workdone is mathematically represented as
where is the potential energy at 180° which is mathematically evaluated as
Where the negative signifies that it is acting against the field
substituting values
and
is the potential energy at 0° which is mathematically evaluated as
substituting values
So