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2 years ago

What is the empirical formula for C8H20F4

Chemistry

1 answer:

AfilCa [17]2 years ago

3 0

The given formula of $C_{8} H_{2} O F_{4}$ can be written as $C_{4} H_{10}-C_{4} H_{10}-F_{4}$

Explanation:

Empirical formula is one of the way of representing the structural arrangement of any molecule. With this formula, we can guess the nearest atom or element in a heterogeneous molecules. Mostly the empirical and molecular formula differs for organic compounds.

As in organic compounds consists of chain of carbon and hydrogen elements. So while arranging them in a relation, we should remember that carbon should contain 4 nearby atoms and hydrogen can share only one electron to its nearby atom. Thus, a carbon can have three hydrogen and one carbon as neighbouring element.

So the given formula of $C_{8} H_{2} O F_{4}$ can be written as

$C_{4} H_{10}-C_{4} H_{10}-F_{4}$

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Answer: (Kr) 5s2

Explanation:

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2 years ago

Which of the following properties of an unknown substance would allow it to be classified as a mixture? The unknown substance

Nadya [2.5K]

Answer:

D. has different properties when sampled in different areas.

Explanation:

The general property of a mixture says that each substance or component in a mixture has its individual or different property which can be separated on the basis of different methods.

Such as a mixture of oil and water is a heterogeneous mixture and have different properties or different densities, which helps them to be sampled in different areas.

Hence, the correct answer is "D".

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2 years ago

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

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2 years ago

What is the volume of 2 mol of chlorine gas at STP? 2.0 L 11.2 L 22.4 L 44.8 L

nirvana33 [79]

Answer:

44.8 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At Standard temperature and pressure (STP);

P = 1 atm

T = 273K

Hence, when n = 2moles, the volume of the gas is:

Using PV = nRT

1 × V = 2 × 0.0821 × 273

V = 44.83

V = 44.8 L

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2 years ago

Alkanes are chains of carbon atoms surrounded by hydrogen atoms. a. True b. False

Ne4ueva [31]

Answer:

a. True

Explanation:

Alkanes are chains of carbon atoms surrounded by hydrogen atoms. TRUE.

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2 years ago