The change in position of an object per unit of time is referred to as

PLEASE HELP it takes tsooo long! lol ima fail! please help! thanks!

Natasha_Volkova [10]

Answer:

A and c, hope i helped xx

Explanation:

4 0

3 years ago

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A 40 kg boy on a skateboard throws a 2 kg ball at 20 m/s to the left. How fast did the boy move to the right on his skateboard?

sergey [27]

According to my examination I have confirmed that I do NOT repeat do NOT know this .

4 0

2 years ago

A ball is attached to a string of length 3 m to make a pendulum. The pendulum is placed at a location that is away from the Eart

Musya8 [376]

1) $0.61 m/s^2$

2) 13.9 s

Explanation:

1)

The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.

It can be calculated using the equation:

$g=\frac{GM}{r^2}$ (1)

where

G is the gravitational constant

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

r is the distance of the object from the Earth's center

The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is

$r=4R$

where

$R=6.37\cdot 10^6 m$ is the Earth's radius

Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):

$g=\frac{GM}{(4R)^2}=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})0.}{(4\cdot 6.37\cdot 10^6)^2}=0.61 m/s^2$

2)

The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration due to gravity at the location of the pendulum

Note that the period of a pendulum does not depend on its mass.

For the pendulum in this problem, we have:

L = 3 m is its length

$g=0.61 m/s^2$ is the acceleration due to gravity (calculated in part 1)

Therefore, the period of the pendulum is:

$T=2\pi \sqrt{\frac{3}{0.61}}=13.9 s$

4 0

3 years ago

A 1.5-kg block slides at rest starts sliding down a snow-covered hill Point A, which has an altitude of 10 m. There is no fricti

damaskus [11]

Answer:

the speed of the block when it reaches point B is 14 m/s

Explanation:

Given that:

mass of the block slides = 1.5 - kg

height = 10 m

Force constant = 200 N/m

distance of rough surface patch = 20 m

coefficient of kinetic friction = 0.15

In order to determine the speed of the block when it reaches point B.

We consider the equation for the energy conservation in the system which can be represented by:

$\dfrac{1}{2}mv^2=mgh$

$\dfrac{1}{2}v^2=gh$

$v^2=2 \times g \times h$

$v^2=2 \times 9.8 \times 10$

$v=\sqrt{2 \times 9.8 \times 10$

$v=\sqrt{196$

v = 14 m/s

Thus; the speed of the block when it reaches point B is 14 m/s

7 0

3 years ago

9. Complete the following statement:

mario62 [17]

Answer:

E) the flow of energy due to a temperature difference.

Explanation:

Heat can be described as the flow of energy due to a temperature difference.

Which is expressed mathematically as;

H = MCΔT

Where;

H is the quantity of heat in a body, measured in Joules

M is the mass of the body, measured in kg

C is the specific heat capacity of the body, J/kg.K

ΔT is change in temperature or temperature difference.

So, heat energy in any system flows from a hotter region to a colder region due to temperature difference.

E) the flow of energy due to a temperature difference.

7 0

3 years ago