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2 years ago

Why do footballers need power?

2 answers:

7 0

<em><u>Power is required for footballers because they has to run long distances in the field, they have to kick, and have to be very quick. So, they require high power.</u></em>

Sedaia [141]2 years ago

4 0

Mass-Energy is constant. If you are working then you are doing it spending energy. If you have a working rate so u also have a energy spending rate, which is called the power. As footballers working rate is too high(running, kicking, jumping, tackling, defensing etc)their energy spending rate i.e, required power is also high. Hence to be a footballer you need high power.

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The speed at which a wave is transmitted depends on _____. A. the state of matter of the medium B. whether or not the wave is re

11Alexandr11 [23.1K]

Answer: C

Explanation:

4 0

2 years ago

During which phase does the arrangement of water molecules become more orderly?

erastovalidia [21]

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3 years ago

An object is pulled along the ground by exerting a force of 35 pounds a rope that makes a 10° angle with the ground. How much wo

GREYUIT [131]

<h2>Answer:</h2>

Workdone = 601.33 Nm

<h2>Explanation:</h2>

Workdone = Force(F) x horizontal distance(d).

Wordone = F x d

Where F is the horizontal component of the force

Force = 35 pounds

Recall that;

1 pound force = 4.4N

=> 35 pounds = 35 x 4.4N = 154N

=> Force = 154N

But since the rope makes a 10⁰ angle with the ground,

The horizontal component of the force F is Force x cos10⁰

=> F = 154 cos 10⁰

=> F = 154 x 0.9848

=> F = 151.66N

Horizontal distance (d) = 13 feet

Recall that;

1 foot = 0.305m

=> 13 feet = 13 x 0.305m = 3.965m

=> d = 3.965m

=> Substituting the values of F and d into the equation above, we have;

Workdone = F x d

Workdone = 151.66N x 3.965m

Workdone = 601.33Nm

8 0

3 years ago

BB8 is an intergalactic robot (essentially a soccer ball with a half meter radius that can control how fast it rolls around) tha

hram777 [196]

Answer:

20 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

r = Radius of robot = 0.5 m

$\alpha$ = Angular acceleration = 2 rad/s²

Linear acceleration is given by

$a=r\alpha\\\Rightarrow a=0.5\times 2\\\Rightarrow a=1\ m/s^2$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 50=0t+\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow t=10\ s$

While speeding up time taken is 10 seconds

$v=u+at\\\Rightarrow v=0+1\times 10\\\Rightarrow v=10\ m/s$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 50=10t-\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow 50=10t-0.5t^2\\\Rightarrow -5t^2+100t-500=0$

$t=\dfrac{-100\pm \sqrt{100^2-4\left(-5\right)\left(-500\right)}}{2\left(-5\right)}\\\Rightarrow t=10\ s$

The time taken to slow down is 10 seconds

Total time the trial is rum is 10+10 = 20 seconds

6 0

2 years ago

If the heat necessary to warm 565.0 g of water from a temperature of T1 = 22.0 °C to T2 = 80.0 °C were somehow converted to tran

densk [106]

Answer:

696.83 m/s

Explanation:

m = mass of water = 565 g = 0.565 kg

c = specific heat of water = 4186 J/(kg⁰C)

ΔT = Change in temperature = T₂ - T₁ = 80 - 22 = 58 ⁰C

v = speed gained by water

Using conservation of energy

Kinetic energy gained by water = heat required to warm water

(0.5) m v² = m c ΔT

(0.5) v² = c ΔT

(0.5) v² = (4186) (58)

v = 696.83 m/s

3 0

3 years ago