All categories

3 years ago

Why do footballers need power?

2 answers:

7 0

<em><u>Power is required for footballers because they has to run long distances in the field, they have to kick, and have to be very quick. So, they require high power.</u></em>

Sedaia [141]3 years ago

4 0

Mass-Energy is constant. If you are working then you are doing it spending energy. If you have a working rate so u also have a energy spending rate, which is called the power. As footballers working rate is too high(running, kicking, jumping, tackling, defensing etc)their energy spending rate i.e, required power is also high. Hence to be a footballer you need high power.

You might be interested in

Which is harder, air tight or water tight seals?

Vladimir [108]

Should be an air tight seal

4 0

4 years ago

A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)

adelina 88 [10]

Answer:

The student is going at the bottom of the slide with a velocity of 8.66 m/s

Explanation:

Given;

mass of the student, m = 74 kg

height of the water slide, h = 11.3 m

work done, W = -5.42 × 10³ J

Apply work energy theorem;

$W = \frac{1}{2}mv_f^2+ mgh_f-(\frac{1}{2}mv_o^2 + mgh_o)\\\\ W + \frac{1}{2}mv_o^2 + mgh_o -mgh_f= \frac{1}{2}mv_f^2\\\\ W + \frac{1}{2}mv_o^2 +mg(h_o-h_f) = \frac{1}{2}mv_f^2\\\\\frac{W}{m} + \frac{1}{2} v_o^2 + g(h_o-h_f) = \frac{1}{2}v_f^2\\\\\frac{2W}{m}+ v_o^2 + 2g(h_o-h_f) = v_f^2\\\\v_f = \sqrt{\frac{2W}{m}+ v_o^2 - 2g(h_f-h_o)} \\\\v_f = \sqrt{\frac{2(-5.42*10^3)}{74}+ (0)^2 - 2*9.8(-11.3)}\\\\v_f=\sqrt{-146.4865+221.48} \\\\v_f = \sqrt{74.9935} \\\\v_f = 8.66 \ m/s$

Therefore, the student is going at the bottom of the slide with a velocity of 8.66 m/s

7 0

3 years ago

Need help don't have much time left

klemol [59]

my dude it is #1 that is my answer

7 0

3 years ago

bija089 [108]

Cathode rays are negatively charged

Explanation:

Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude that the rays were negatively charged.

Cathode rays were discovered by J.J. Thomson based on his experiment on the gas discharge tube. He was able to discover some of the properties of the wave.

One notable one was that he observed that the rays deflected towards the positively charged plate.

Since unlike poles attract then he concluded that the cathode rays were negatively charged.

learn more:

Rutherford brainly.com/question/1859083

#learnwithBrainly

6 0

4 years ago

1. Explain the following terms i. Design ii. Possible solution iii. Specification.

Furkat [3]

Answer:

phpgodigpfogpglxjccxnckxjccll

3 0

3 years ago