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3 years ago

Why do footballers need power?

2 answers:

7 0

Power is required for footballers because they has to run long distances in the field, they have to kick, and have to be very quick. So, they require high power.

Sedaia [141]3 years ago

4 0

Mass-Energy is constant. If you are working then you are doing it spending energy. If you have a working rate so u also have a energy spending rate, which is called the power. As footballers working rate is too high(running, kicking, jumping, tackling, defensing etc)their energy spending rate i.e, required power is also high. Hence to be a footballer you need high power.

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What is the magnitude of the gravitational force of attraction between two 0.425-kilogram soccer balls when the distance between

Lapatulllka [165]

Answer

4.8212×10⁻¹¹ N

Explanation

The gravitational force F, between 2 masses m₁ and m₂ is given by:

F = (Gm₁m₂)/d²

Where G = 6.673 x 10⁻¹¹ N m²/kg² and d is the distance between the 2 masses.

F = (Gm₁m₂)/d²

= (6.673 x 10⁻¹¹ × 0.425 × 0.425)/0.500²

= 1.2053×10⁻¹¹/0.25

= 4.8212×10⁻¹¹ N

7 0

3 years ago

What are the 3 main types of global winds in the northern hemisphere?

sveta [45]

Answer:

The trade winds, the prevailing westerlies, the polar easterlies.

Explanation:

There are three prevailing wind belts associated with these cells: the trade winds, the prevailing westerlies, and the polar easterlies (Fig. 3.10). Fig. 3.10 only shows the circulation cells and winds in the Northern Hemisphere

8 0

3 years ago

The internal energy of a system....

Angelina_Jolie [31]

Answer:

C. Equals the sum of all forms of energy contained within the system.

D. Equals the heat entering the system at constant volume.

E. Equals the heat entering the system plus the work done on the system

Explanation:

Internal energy is defined as the sum of internal kinetic energy and internal potential energy, that is, the energy contained within the system.

The first law of thermodynamics relates the change in the internal energy with the heat entering the system (Q) and work done on the system (W), with the following expression:

$\Delta U=Q+W$

If the system is at constant volume the work done is zero. Therefore, the heat entering the system increases its internal energy:

$\Delta U=Q$

5 0

3 years ago

Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they

Svetradugi [14.3K]

Answer: Graph C is the correct option

Explanation:

The question is incomplete, please remember to submit the whole question :)

However, the rest of the question with its corresponding figures is below:

Assume that positive momentum is to the right, which of the following best represents the momentum of the cart of mass m as a function of time before and after the collision?

The initial momentum $p_{o}$ of the cart with mass $m$ (before the collision) is:

$p_{o}=-mV$ (1) Note the negative sign indicates the direction of cart's velocity (to the left, as seen in the first image attached)

On the other hand, the final momentum $p_{f}$ of both carts (after the inelastic collision) is:

$p_{f}=(2m+m) V_{f}=3m V_{f}$ (2)

So, according to this, the correct graph tha best represents the situation is C. Since before the collision the momentum is negative, then both carts slow down after the collision ( $V_{f}$ ), and taking into account the linear momentum is directly proportional to the velocity $p_{f}$ (although is in the positive direction) is less than $p_{o}$ .