Ask question

Ask question

All categories

2 years ago

13

When a single source of light shines through an extremely thin rectangular slit and projects on a far away viewing screen, a sin

gle rectangular region of the viewing screen is illuminated (matching the shape of the thin rectangular slit).
O True O False

1 answer:

saveliy_v [14]2 years ago

7 0

True
If it helps you plz brainlest me

You might be interested in

An astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?

Kamila [148]

Answer:

The answer is

<h2>28 kg</h2>

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

$m = \frac{p}{v} \\$

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

$m = \frac{280}{10} = 28 \\$

We have the final answer as

<h3>28 kg</h3>

Hope this helps you

3 0

3 years ago

How do you solve 0.004 dm + 0.12508 dm?

Effectus [21]

0.004 of something added to 0.12508 of the same thing
adds up to 0.12908 of it.

The thing could be a glass of water, a sheet of paper,
a pound of ground beef, a gallon of gas, or a snowball.
In this problem, it just happens to be a dm.

7 0

2 years ago

A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn

Rus_ich [418]

Answer:

(A) It will take 22 sec to come in rest

(b) Work done for coming in rest will be 0.2131 J

Explanation:

We have given the player turntable initially rotating at speed of $33\frac{1}{3}rpm=33.333rpm=\frac{2\times 3.14\times 33.333}{60}=3.49rad/sec$

Now speed is reduced by 75 %

So final speed $\frac{3.49\times 75}{100}=2.6175rad/sec$

Time t = 5.5 sec

From first equation of motion we know that '

$\alpha =\frac{\omega -\omega _0}{t}=\frac{2.6175-3.49}{4}=-0.158rad/sec^2$

(a) Now final velocity $\omega =0rad/sec$

So time t to come in rest $t=\frac{0-3.49}{-0.158}=22sec$

(b) The work done in coming rest is given by

$\frac{1}{2}I\left ( \omega ^2-\omega _0^2 \right )=\frac{1}{2}\times 0.035\times (0^2-3.49^2)=0.2131J$

4 0

2 years ago

A positive charge and a negative charge held a certain distance apart are released. as they move, the force on each particle:___

iVinArrow [24]

A positive charge and a negative charge held a certain distance apart are released. as they move, the force on each particle increases

The most common charge carriers are the positively charged proton and the negatively charged electron. The movement of any of these charged particles constitutes an electric current

<h3>What is a Charge ?</h3>

When there are more or fewer protons in an atom than electrons, the substance has an electric charge. Protons have a positive charge, while electrons have a negative charge. If a substance has more protons than electrons, it is positively charged; if it has more electrons, it is negatively charged.

The SI units for charge are ampere-second or coulomb. When one ampere of electric current goes through the conductor for one second, one coulomb of charge passes through it. Charge is denoted by the formula Q = I t.

Learn more about Charge here:

brainly.com/question/18102056

#SPJ4

7 0

1 year ago

A crate is pushed horizontally by a horizontal force 527.018 N . Sliding friction resists the motion, and the kinetic coefficien

gulaghasi [49]

Answer:

m= 10 kg a = 52 m / s²

Explanation:

For this problem we must use Newton's second law, let's apply it to each axis

X axis

F - fr = ma

The equation for the force of friction is

-fr = miu N

Axis y

N- W = 0

N = mg

Let's replace and calculate laceration

F - miu (mg) = ma

a = F / m - mi g

a = 527.018 / m - 0.17 9.8

We must know the mass of the body suppose m = 10 kg

a = 527.018 / 10 - 1,666

a = 52 m / s²

5 0

3 years ago