Question

How many liters of 4.0 NaOH solution will react with 1.8 mol H2SO4

Answer 1

Answer:

0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.

Explanation:

$2NaOH(aq)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

According to reaction, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide.

Then 1.8 moles of sulfuric acid will react with:

$\frac{2}{1}\times 1.8 mol=3.6 mol$ moles of NaOH.

Molarity of NaOH = 4.0 M

Moles of NaOH= n = 3.6 mol

Volume of NaOH = V

$M=\frac{n}{V(L)}$

$V=\frac{n}{M}=\frac{3.6 mol}{4.0 M}=0.9 L$

0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.