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2 years ago

How does urban sprawl affect water consumption?

Chemistry

2 answers:

Vesnalui [34]2 years ago

5 0

Answer:

Urban sprawl is the development in urban areas

Due to which people are migrating from rural areas to urban areas to get the jobs or their income sources due to the opportunities.

So, as population is increasing in the urban areas. The food consumption and water consumption will also increase.

So, this is how urban sprawl affect water consumption.

n200080 [17]2 years ago

4 0

Water consumption rises because suburban communities use more water

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When heated zinc carbonate decomposed to form zinc oxide and carbon dioxide gas how do you knke decomposition is complete

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Answer:

This reaction is characteristic to metal carbonates, which decompose when heated to form the oxide of the metal and carbon dioxide gas.

Explanation:

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2 years ago

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Which characteristic is a property of water

likoan [24]

It is made of polar molecules

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2 years ago

As you have seen, ozone is formed in the upper atmosphere through the reaction:

baherus [9]

The rate law equation for Ozone reaction

r=k[O][O₂]

<h3>Further explanation</h3>

Given

Reaction of Ozone :.

O(g) + O2(g) → O3(g)

Required

the rate law equation

Solution

The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants

For reaction

aA + bB ⇒ C + D

The rate law can be formulated:

$\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}$

where

r = reaction rate, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

So for Ozone reaction, the rate law (first orde for both O and O₂) :

$\tt \boxed{\bold{r=k[O][O_2]}}$

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2 years ago

A hot air balloon is filled with 1.31 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 121 ∘ C . Wha

victus00 [196]

Answer:

$1.82\times 10^6 L$ is the volume of the air in the balloon after it is heated.

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$ (at constant pressure)

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1= 1.31\times 10^6 L\\T_1=11^oC=(11+273.15)K=284.15K\\V_2=?\\T_2=121^oC=(121+273.15)K=394.15 K$

Putting values in above equation, we get:

$\frac{1.31\times 10^6 L}{284.15 K}=\frac{V_2}{394.14 K}\\\\V_2=\frac{V_1\times T_2}{T_1}$

$V_2=1.82\times 10^6 L$

$1.82\times 10^6 L$ is the volume of the air in the balloon after it is heated.

4 0

3 years ago

Calculate the number of photons having a wavelength of 12.0 μm required to produce 1.0 kJ of energy.

nika2105 [10]

Answer:

N = 603.32 × 10 ²⁰

Explanation:

Given data:

Wavelength of photon = 12.0 μm or 12 × 10 ⁻⁶ m

Energy = 1.0 KJ or 1000 j

Number of photons = ?

Solution:

Formula:

E = n . h . f

E = energy

N = number of photons

h = planck's constant

f = frequency

it is known that

f = c/λ

thus,

E = N . h . c / λ

Now we will put the values in formula.

1000 j = ( N. 6.63 × 10 ⁻³⁴ j.s × 3 × 10⁸ m/s ) / 12 × 10 ⁻⁶ m

N = 1000 j ×12 × 10 ⁻⁶ m / 6.63 × 10 ⁻³⁴ j.s × 3 × 10⁸ m/s

N = 12000 j × 10 ⁻⁶ m / 19.89 × 10 ⁻²⁶ j. m

N = 603.32 × 10 ²⁰

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2 years ago