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Virty [35]
3 years ago
8

Which sound wave features are being described?

Physics
2 answers:
densk [106]3 years ago
8 0
<h2>Answer:</h2>

Number of wavelengths

-----------------------------------  :  ⇒ Frequency

              Time

Distance traveled

--------------------------  :  ⇒ Speed

          Time

Andre45 [30]3 years ago
6 0

Answer: Sound wave can be described by five characteristics Wavelength , amplitude, time period, frequency and velocity or speed

Explanation:

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Ilia_Sergeevich [38]
Velocity, wavelength, and frequency.

Wave velocity (v) is how fast a wave propagates in a given medium. Its unit is meter per second. Check the speed calculator for more information about speed and velocity.

Wavelength (λ) is the distance over which the shape of a wave repeats. It depends on the medium in which a wave travels. It is measured in meters.

Frequency (f) of a wave refers to how many times (per a given time duration) the particles of a medium vibrate when the wave passes through it. The unit of frequency is Hertz or 1/second.
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3 years ago
Why is gravitational acceleration almost always a factor in determining pressure?
Scorpion4ik [409]

Explanation:

Newton's law of universal gravitation states that every object attracts every other object with a force. For any two objects, this force is directly proportional to the mass of each object. The greater the masses, the greater the force of attraction between them. Newton also deduced that this force decreases as the square of the distance between the centers of the objects increases. The farther away the objects are from each other, the less the force of attraction between them.

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3 years ago
State one advantage and disadvantage of friction
yuradex [85]

Answer:

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Disadvantage:

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5 0
2 years ago
An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa
Natali [406]

Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

F=G*\frac{m_a*m_p}{r^2}

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2

so:

m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg

7 0
4 years ago
Compare these two waves.
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