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FromTheMoon [43]
4 years ago
5

Suppose the roller-coaster car in fig.6–41 passes point 1 with a speed of if the average force of friction is equal to 0.23 of i

ts weight, with what speed will it reach point 2? the distance traveled is 45.0 m.
Physics
1 answer:
madreJ [45]4 years ago
8 0

The values in figure 1 shows h1 = 39 m, h2 = 13 m, h3 = 25 with a speed of 1.5m/s

 

The Initial speed u = 1.5m/s.

Vertical distance covered between point 1 and point 2 is (39-13) =26m

The expanse 45 m is equal to a height of (45/6) =7.5 (As frictional force is mg/6)

With the kinematics equation v^2 =u^2 + 2as

V^2 = 1.5^2 + 2*9.8 (26 + 7.5)

V = 25.7 m/s

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The concept required to solve this problem is quantization of charge.

First the number of electrons will be calculated and then the total mass of the charge.

With these data it will be possible to calculate the percentage of load in the mass.

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Replacing,

n = \frac{4*10^{-6}C}{1.6*10^{-19}}

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According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron

The total mass of the charge is

m= nm_e

Here,

m = Mass of the charge

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Replacing we have

\text{Percentage change} = \frac{(2.5*10^13)(9.1*10^{-28})}{33}*100

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6 0
4 years ago
long, straight, vertical wire carries a current upward. Due east of this wire, in what direction does the magnetic field point?
Kamila [148]

Answer:

The correct answer to the question is;

North

Explanation:

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6 0
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If Susan exerted a force of 5 newtons and the output force of the machine is 15
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Answer:

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Explanation:

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MA = Output force/Input force = 15 N/ 5 N = 3

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Artyom0805 [142]
57.0 kg is the answer
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BabaBlast [244]

Answer:

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